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a square area will be 8x8=64. Formula is a2 + b2 = c2. In other words the square root of (8x8 + 8x8) 128 which is 11.31371

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Q: What is the length of the diagonal of a square with an area of 64?
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What is the length of the diagonal of a square whose area is 64 cm2?

The square's diagonal is 11.314 cm


What is the length of the diagonal of a square who's area is 64cm squared?

Area = 64 cm2 so length of side = 8cm Then, by Pythagoras, length of diagonal = sqrt[82 + 82] = 8*sqrt(2) = 11.3137 cm (to 4 dp)


What is the length of each side of a square with an area of 64?

The length of each side of a square with an area of 64 is: 8.


The length of a diagonal of a square is 8 cm What is the length of each side of the square?

About 5.656854249 cm using Pythagoras' theorem: 2x2 = 64


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Firstly you need to work out the length of a side. Using Pythagorean Theorem for a right angled triangle a2+b2=c2 where a = the length, b = height & c = diagonal since c = 8 and a = b are the same 2a2 = 64 a2 = 32 a = 5.657 cm since the area of the square is a2 then area = 32cm2


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What is the area of a square with side lenghts of 8?

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What If the area of a square is 64 square centimeters what's the length of one side?

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