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To find the length of the diagonal of a square with an area of 64 square units, we first need to calculate the side length of the square. Since the area of a square is side length squared (A = s^2), we can find the side length by taking the square root of the area (s = √A). In this case, the side length of the square is 8 units.
To find the length of the diagonal, we can use the Pythagorean theorem, which states that the square of the length of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides (a^2 + b^2 = c^2). Since a square can be divided into two right triangles with the diagonal as the hypotenuse, we can calculate the diagonal length using d = √(s^2 + s^2), where d is the diagonal length and s is the side length.
Substituting the side length of 8 units into the formula, we get d = √(8^2 + 8^2) = √(64 + 64) = √128 = 8√2 units. Therefore, the length of the diagonal of a square with an area of 64 square units is 8√2 units.
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What is the length of the diagonal of a square who's area is 64cm squared?
Area = 64 cm2 so length of side = 8cm Then, by Pythagoras, length of diagonal = sqrt[82 + 82] = 8*sqrt(2) = 11.3137 cm (to 4 dp)
The length of a diagonal of a square is 8 cm What is the length of each side of the square?
About 5.656854249 cm using Pythagoras' theorem: 2x2 = 64
What is the area of a square with sides of length 8?
The area of a square is calculated by multiplying the length of one side by itself. In this case, with sides of length 8, the area would be 8 x 8 = 64 square units.
What If the area of a square is 64 square centimeters what's the length of one side?
8
How do you find the length of a diagnol of a square if the perimeter is 64 cm?
If the perimeter is 64, then one side is 16. The diagonal is the hypotenuse of a right triangle. Hello Pythagoras. The answer is the square root of 512 or 16 times the square root of 2.
