What is the length of the diagonal of a square with an area of 64?

Answer 1

To find the length of the diagonal of a square with an area of 64 square units, we first need to calculate the side length of the square. Since the area of a square is side length squared (A = s^2), we can find the side length by taking the square root of the area (s = √A). In this case, the side length of the square is 8 units.

To find the length of the diagonal, we can use the Pythagorean theorem, which states that the square of the length of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides (a^2 + b^2 = c^2). Since a square can be divided into two right triangles with the diagonal as the hypotenuse, we can calculate the diagonal length using d = √(s^2 + s^2), where d is the diagonal length and s is the side length.

Substituting the side length of 8 units into the formula, we get d = √(8^2 + 8^2) = √(64 + 64) = √128 = 8√2 units. Therefore, the length of the diagonal of a square with an area of 64 square units is 8√2 units.

Answer 2

a square area will be 8x8=64. Formula is a2 + b2 = c2. In other words the square root of (8x8 + 8x8) 128 which is 11.31371