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What is the area of a triangle whose base is 12cm and an altitude of 10cm?
The area of triangle is : 60.0
What is the area of a triangle with a base of 10 meters and a height of 20 meters?
The area of triangle is : 100.0
A triangle has a base of 10 centimeters and a height of 7 centimeters Which is the total area of the triangle?
The formula to calculate the area of a triangle is Half (Base x Height). So 10 x 7 = 70 and 70 divided by 2 = 35. The area of the triangle is 35 square centimeters.
The lenght of one side of an equilateral triangle is 10 cm find the altitude of the triangle?
The triangle's altitude is 8.7 (8.66025) cm.
How do you find an area of a triangle with a base 9 and a height 10?
Area of a triangle = (base x height) / 2, so (9x10)/2 = 90/2 = 45.
How do you calculate the altitude of a triangle?
Let the given area is 10cm. Base of the triangle is 4 cm. altitude of triangle=? Area= 1/2 x Base x altitude 10= 1/2 x 4x altitude 10=2 x altitude 10/2= altitude 5= altitude Hence, altitude of the triangle is 5 cm.
What is the area of a triangle with a base of 14 and altitude of 10?
70
How do you find area of triangle with base 10 feet and altitude 9 feet?
Area of a triangle = 1/2*base*altitude in square units Area = 45 square feet
What is the area of a triangle whose base is 12cm and an altitude of 10cm?
The area of triangle is : 60.0
A triangle has a base of 10 and an altitude of 14. What is the area?
It is: 0.5*10*14 = 70 square units
What is the base of an obtuse angled triangle with an area of 32cm squared and a perpendicular height of 6cm?
Area = base x altitude /2 so base = 2 x area/altitude = 64/6 = 10 & 2/3 cm.
What is the area of a triangle with the base of 10 and the height of 12?
The area of triangle is : 60.0
The altitude drawn to the base of an isosceles triangle is 8cm and the perimeter is 32cm Find the area of the triangle?
To have an altitude of 8 cm it could have a base of 12 cm and two equal sides of 10 cm which would satisfy Pythagoras' theorem because an isosceles triangle is in fact two right angle triangles joined together. Area of a triangle = 1/2*base*height Area = 1/2*12*8 = 48 square cm
Area of a triangle base of 10 and a height of 15?
The area of a triangle is (1/2) x (length of the base) x (height of the triangle). You ought to be able to handle it from this point.
Find the area of an equilateral triangle with side 10?
Finding the perpendicular height of the triangle by using Pythagoras works out at about 8.660254038. 1/2*base*perpendicular height or altitude = area 1/2*10*8.660254038 = 43.30127019 square units
What is the area of a triangle with a base of 10 inches and an altitude of 14 inches?
The formula for area of a triangle is A = bh/2 where b is the base and h is the heigth. multipy b x h and then divide by 2 to find the area. Based on the values given, multiply 10 x 14 and then divide by 2: 10 x 14 = 140 / 2 = 70 sq in
What is the area of a triangle with base 2cm and height 5cm?
To find the area of a triangle, you use the formula: Area = 1/2 * base * height. In this case, the base is 2cm and the height is 5cm. Plugging these values into the formula, we get: Area = 1/2 * 2cm * 5cm = 5 square centimeters. Therefore, the area of the triangle is 5 square centimeters.
