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The triangle's altitude is 8.7 (8.66025) cm.

Q: The lenght of one side of an equilateral triangle is 10 cm find the altitude of the triangle?

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28.75m

It is called and equilateral triangle. You can find more information about equilateral polygons here: http://www.answers.com/equilateral

Find the area of an equilateral triangle if its perimeter is 18 ft

Side = 6 cm 1/2 of the base = 3 cm Altitude = 3 times square-root of 3 = 5.196 cm (rounded)

each angle is 60 degrees. If you know trigonometry sin 60 = Altitude/length of side (from Pythagoras) A = 9.526 inch Or, from Pythagoras theorem 5.5 squared + Altitude squared = 11 squared Altitude = 9.526

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28.75m

Altitude = 10.4 (10.3923) cm

Here are a couple Find the altitude of a triangle with base 3 and hypotenuse 5. Find the altitude of an equilateral triangle with each side to 2

The altitude of an equilateral triangle is (√3)/2*a. where 'a' is the side of the triangle. It can be just find by giving a perpendicular to the base of the triangle, the base of the triangle become a/2 and one side is a. so by applying Pythagoras theorem we will get the desired formula.

The length of each side is 9.2376 cm. (rounded)

An equilateral triangle has 3 equal interior angles each of 60 degrees. There are two right angled triangles in an equilateral triangle. So we can use trigonometry to find the length of one side of the equilateral triangle then multiply this by 3 to find its perimeter. Hypotenuse (which is one side of the equilateral) = 15/sin 60 degrees = 17.32050808 17.32050808 x 3 = 51.96152423 Perimeter = 51.96152423 units.

9.794747317 m (with the help of Pythagoras' theorem)

Multiply the altitude by [ 2 / sqrt(3) ] to get the length of the side.[ 2 / sqrt(3) ] is about 1.1547 (rounded)

Since an equilateral triangle has three congruent sides (and 3 congruent angles, each of 60⁰), the length of each side is 32/3 cm. If we draw one of the altitudes of the triangle, then a right triangle is formed where the side of a triangle is the hypotenuse, and the altitude is opposite to a 60 degrees angle. So we have, sin 60⁰ = altitude/(32/3 cm) (multiply by 32/3 cm to both sides) (32/3 cm)sin 60⁰ = altitude 9.2 cm = altitude

Do you mean an equilateral triangle? Then if so then the formula for the area of any triangle: 0.5*a*b*sinC whereas a and b are the embraced sides of angle C And in the case of an equilateral triangle it is: 0.5*any side squared*sin(60 degrees) Alternatively use Pythagoras' theorem to find the altitude of the triangle then use: 0.5*base*height = area

You can't as there is no hypotenuse in an equilateral triangle. The hypotenuse is the side of a triangle which is opposite a right angle (90°); all angles in an equilateral triangle are 60°.

The altitude of an equilateral triangle bisects the base. So, if the sides of the triangle were l cm, the altitude forms a right angled triangle with sides h, l/2 and hypotenuse l cm. Then, by Pythagoras, h2 = 3l2 / 4 so that h = l*sqrt(3)/2 and then area = l*h/2 = l*[l*sqrt(3)/2]/2 =l2*sqrt(3)/4