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The lenght of one side of an equilateral triangle is 10 cm find the altitude of the triangle?
Wiki User
∙ 13y ago
The triangle's altitude is 8.7 (8.66025) cm.
Wiki User
∙ 13y ago
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The altitude of an equilateral triangle is 8.3m. find the perimeter?
28.75m
What is a triangle called that has 3 equal sides and 3 equal angles?
It is called and equilateral triangle. You can find more information about equilateral polygons here: http://www.answers.com/equilateral
The length of one side of an equilateral triangle is 11 Find the length of the altitude?
each angle is 60 degrees. If you know trigonometry sin 60 = Altitude/length of side (from Pythagoras) A = 9.526 inch Or, from Pythagoras theorem 5.5 squared + Altitude squared = 11 squared Altitude = 9.526
Find the length of the altitude of an equilateral triangle if one side has a length of 6cm?
Side = 6 cm 1/2 of the base = 3 cm Altitude = 3 times square-root of 3 = 5.196 cm (rounded)
What is the area of an equilateral triangle that has a perimeter of 71 feet?
Find the area of an equilateral triangle if its perimeter is 18 ft
The altitude of an equilateral triangle is 8.3m. find the perimeter?
28.75m
Find The altitude of an equilateral triangle if one of its sides measures 12cm?
Altitude = 10.4 (10.3923) cm
Example problems in right plane triangle?
Here are a couple Find the altitude of a triangle with base 3 and hypotenuse 5. Find the altitude of an equilateral triangle with each side to 2
What is the length of the altitude of the equilateral triangle?
The altitude of an equilateral triangle is (√3)/2*a. where 'a' is the side of the triangle. It can be just find by giving a perpendicular to the base of the triangle, the base of the triangle become a/2 and one side is a. so by applying Pythagoras theorem we will get the desired formula.
The altitude of an equilateral triangle is 8cm . find the side?
The length of each side is 9.2376 cm. (rounded)
Find the length of an altitude of an equilateral triangle with sides that measure 11.31 m?
9.794747317 m (with the help of Pythagoras' theorem)
What is the perimeter of an equilateral triangle with an altitude of 15?
An equilateral triangle has 3 equal interior angles each of 60 degrees. There are two right angled triangles in an equilateral triangle. So we can use trigonometry to find the length of one side of the equilateral triangle then multiply this by 3 to find its perimeter. Hypotenuse (which is one side of the equilateral) = 15/sin 60 degrees = 17.32050808 17.32050808 x 3 = 51.96152423 Perimeter = 51.96152423 units.
How do you find the length of a side of an equilateral triangle when you know the length of the altitude?
Multiply the altitude by [ 2 / sqrt(3) ] to get the length of the side.[ 2 / sqrt(3) ] is about 1.1547 (rounded)
The perimeter of an equilateral triangle is 32centimeters find the length of an altitude of the triagle to the nearest tenth of a centimeter?
Since an equilateral triangle has three congruent sides (and 3 congruent angles, each of 60⁰), the length of each side is 32/3 cm. If we draw one of the altitudes of the triangle, then a right triangle is formed where the side of a triangle is the hypotenuse, and the altitude is opposite to a 60 degrees angle. So we have, sin 60⁰ = altitude/(32/3 cm) (multiply by 32/3 cm to both sides) (32/3 cm)sin 60⁰ = altitude 9.2 cm = altitude
How do you find the hypotenuse of an equilateral triangle?
You can't as there is no hypotenuse in an equilateral triangle. The hypotenuse is the side of a triangle which is opposite a right angle (90°); all angles in an equilateral triangle are 60°.
How do you find the area of an equalateral triangle?
Do you mean an equilateral triangle? Then if so then the formula for the area of any triangle: 0.5*a*b*sinC whereas a and b are the embraced sides of angle C And in the case of an equilateral triangle it is: 0.5*any side squared*sin(60 degrees) Alternatively use Pythagoras' theorem to find the altitude of the triangle then use: 0.5*base*height = area
Find the area of an equilateral triangle with altitude h cm?
The altitude of an equilateral triangle bisects the base. So, if the sides of the triangle were l cm, the altitude forms a right angled triangle with sides h, l/2 and hypotenuse l cm. Then, by Pythagoras, h2 = 3l2 / 4 so that h = l*sqrt(3)/2 and then area = l*h/2 = l*[l*sqrt(3)/2]/2 =l2*sqrt(3)/4
