Area is 339.48196 m2
To get the area of an equilateral triangle, you just need to know the length of one side. Multiply the length of one side by the square root of three and then divide the product by four, and you will get the area of the triangle.
If the base of a triangle is b and the height of the triangle is h, the area of the triangle is given by the formula: area = 0.5 x b x h.As such, in your case we have 28 = 0.5 x 4 x h, which means that h = 14.
That's an isosceles triangle.
The 110 degree angle makes this triangle an obtuse triangle.
The sum of the internal angles of a triangle is 180 degrees. Since you know this is a right-angled triangle, you know that one side is 90 degrees. If the other angle is 28 degrees, then you know that the remaining angle must be 180 - 90 - 28 = 62 degrees.
To get the area of an equilateral triangle, you just need to know the length of one side. Multiply the length of one side by the square root of three and then divide the product by four, and you will get the area of the triangle.
The triangle with side lengths of 44 mm, 28 mm, and 24 mm is classified as a scalene triangle. This is because all three sides are of different lengths, which is the defining characteristic of scalene triangles. It is not isosceles, as that would require at least two sides to be equal, nor is it equilateral, as all three sides would need to be equal.
No. But they can be the lengths of the three sides.
No. But they can be the lengths of the three sides.
It depends. What shape is it? And is it equilateral or not?
Yes.
Area = 0.5*21*28 = 294 square inches
Area = 0.5*21*28 = 294 square inches
Area of a triangle = 1/2 * base * heightWe have,Area = 28 cm squared, base = 8cmthen,28 = 1/2 * 8 * h28 = 4*hh = 7cm
The right-angle triangle measures 28cm by 35cm. Such a triangle is half of a rectangle.Therefore 28 x 35 = 980cm2 is the area of a rectangle.980 / 2 = 490cm2 will give the area of the triangle (which is 490cm2).
area of a triangle is half the base times the height .5*22*28=308
I assume you want the area of a triangle with side lengths 18 ft, 22 ft and 16 ft. Given the sides of a triangle, its area is given by: area = √(s(s - a)(s - b)(s - c)) Where s is the semi-perimeter, ie s = ½(a + b + c) or triangle with sides 18 ft, 22 ft 16 ft, area is: s = ½(18 + 22 + 16) ft = 28 ft → area = √(28(28 - 18)(28 - 22)(28 - 16)) ft² = √3360 ft² ≈ 57.97 ft²