0
What is the area of an isosceles that has a base of 5 cm and a height of 7 cm?
Wiki User
∙ 10y ago
17.5 sq. cm
Wiki User
∙ 10y ago
Add your answer:
Earn +20 pts
What is the area of an isosceles triangle that has a base of 5 cm and a height of 7cm?
17.5cm squared
What is the base of an isosceles triangle with leg 9 cm and height 6 cm?
Square root of 45.
What is the area of an isosceles triangle with sides measuring 13 13 and 10 cm?
The area of a triangle is (1/2) x base x height. The height is perpendicular to the base. In this case, you can take the 10 cm as the base, and calculate the height with Pythagoras' formula. If you split the base in half now you have two 5-12-13 right triangles, so the height is 12 cm and the area is (1/2)*(10cm)*(12cm) = 60 cm2
What is the area of a triangle with a base of 10Cm and the height of 15Cm?
Area = 1/2 * base * height Area = 1/2(10 cm)(15 cm) = 75 cm2 ======
What is the area of a triangle that has a base of 14 cm and a height of 11 cm?
The area of every triangle is 1/2 of the product of (length of its base times its height).You can probably take it from there.
What is the area of an isosceles triangle where base is 1.1 cm and height is 1.5 cm?
Area = 1/2*base*height = 0.825 sq cm. The fact that the triangle is isosceles is irrelevant: it makes no difference to its area.
What is the area of isosceles triangle that has a base of 5cm and a height of 7cm?
35/2 cm² 0r 17.5 cm² area = 0.5 x base x height
What is the area of an isosceles triangle that has a base of 5cm and a height of 7 cm.?
Area of isosceles triangle: 0.5*5*7 = 17.5 square cm
What is the area of an isosceles triangle that has a base of 5 cm and a height of 7cm?
17.5cm squared
What is the area of an isosceles triangle that has a base of 5 cm and a height of 7 cm?
Area = 1/2*5*7 = 17.5 square cm
Hat is the area of an isosceles triangle that has a base of 5 cm and a height of 7 cm?
1/2*5*7 = 17.5 square cm
What is the area of an isosceles triangle that has a base of 5cm and a height of 7cm?
1/2*5*7 = 17.5 square cm
What is the vertical height of a triangle with an area of 48cm2 and a base length of 6cm?
assuming its an isosceles triangle, then its 16 cm high
How long is the base of the parallelogram if its area is 720 cm squared and 15 cm in height?
Area = Base*Height so Base = Area/Height = 720/15 = 48 cm
What is the area of 9cm 9cm 12cm?
9 cm x 9 cm x 12 cm is an isosceles triangle with base 12 and height = sqrt(81-36) cm = sqrt(45) cm So area = 1/2 * base * height = 1/2 * 12 * sqrt(45) = 40.25 cm2
What is the base of an isosceles triangle with leg 9 cm and height 6 cm?
Square root of 45.
What is the area of an isosceles triangle with sides measuring 13 13 and 10 cm?
The area of a triangle is (1/2) x base x height. The height is perpendicular to the base. In this case, you can take the 10 cm as the base, and calculate the height with Pythagoras' formula. If you split the base in half now you have two 5-12-13 right triangles, so the height is 12 cm and the area is (1/2)*(10cm)*(12cm) = 60 cm2
