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The area of a triangle is (1/2) x base x height. The height is perpendicular to the base. In this case, you can take the 10 cm as the base, and calculate the height with Pythagoras' formula. If you split the base in half now you have two 5-12-13 right triangles, so the height is 12 cm and the area is (1/2)*(10cm)*(12cm) = 60 cm2

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Q: What is the area of an isosceles triangle with sides measuring 13 13 and 10 cm?
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