To find the area of a figure with sides of different lengths, we first need to determine the shape of the figure. In this case, the sides are 5m, 3m, 4m, and 6m, which could form a quadrilateral or a triangle depending on the configuration. If it is a quadrilateral, we would need more information such as the angles between the sides to calculate the area. If it is a triangle, we could use Heron's formula to find the area. More details or a diagram would be necessary to provide an accurate calculation.
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Well, darling, the figure you're describing is a trapezoid, not a quadrilateral, so let's get that straight. To find the area, you can use the formula A = 0.5 * (a + b) * h, where a and b are the lengths of the parallel sides and h is the height between them. Plug in the values and you'll get the area in square meters. Voilà!
It is not possible to answer the question.
The fact that there are four lengths given in the question suggests that the shape is a quadrilateral. Unfortunately, the lengths of a quadrilateral's sides does not determine its area. One way to see this is that a square can be flexed into a rhombus and the top and bottom sides of the rhombus brought closer and closer together until its area is almost zero.
It is not possible to answer the question.
The fact that there are four lengths given in the question suggests that the shape is a quadrilateral. Unfortunately, the lengths of a quadrilateral's sides does not determine its area. One way to see this is that a square can be flexed into a rhombus and the top and bottom sides of the rhombus brought closer and closer together until its area is almost zero.
It is not possible to answer the question.
The fact that there are four lengths given in the question suggests that the shape is a quadrilateral. Unfortunately, the lengths of a quadrilateral's sides does not determine its area. One way to see this is that a square can be flexed into a rhombus and the top and bottom sides of the rhombus brought closer and closer together until its area is almost zero.
It is not possible to answer the question.
The fact that there are four lengths given in the question suggests that the shape is a quadrilateral. Unfortunately, the lengths of a quadrilateral's sides does not determine its area. One way to see this is that a square can be flexed into a rhombus and the top and bottom sides of the rhombus brought closer and closer together until its area is almost zero.
It is not possible to answer the question.
The fact that there are four lengths given in the question suggests that the shape is a quadrilateral. Unfortunately, the lengths of a quadrilateral's sides does not determine its area. One way to see this is that a square can be flexed into a rhombus and the top and bottom sides of the rhombus brought closer and closer together until its area is almost zero.
-15m but -15 metres doesnt exist
To find the area of a quadrilateral with sides of 7m, 4m, 5m, and 3m, you can use Brahmagupta's formula for the area of a cyclic quadrilateral: Area = √(s-a)(s-b)(s-c)(s-d), where s is the semiperimeter (s = (a + b + c + d) / 2) and a, b, c, and d are the lengths of the sides. Plug in the values of the sides into the formula to calculate the area.
-3m = 5m+8 -3m-5m = 8 -8m = 8 m = -1
To solve the equation 5m + 3 = 3m + 9, you need to isolate the variable m. Start by subtracting 3m from both sides to get 2m + 3 = 9. Then, subtract 3 from both sides to get 2m = 6. Finally, divide by 2 to find m = 3.
4m+9+5m-12=42 9m=45 m=5