Working Out:
1+2+3+4+5+997+998+999+1000=4009
4009/9=445.4444444
*Note we divided by 9 because there were a total of 9 numbers in the set.*
996 997 998 999
1001
500.5 Because: 1+2+3+.......998+999+1000 Add 1 to 1000 equaling 1001. This makes a pair. There are 500 more of these so 500 pairs. So 1001x500= 500500 Finally divide it by 1000 because there are 1000 numbers. (1000-1=999+1=1000) Concluding the answer to be 500.5 :)
When you sum 998 with 1.
999 + (999/999) = 1000
There are 998 of them: 2, 3, 4, 5, ... , 996, 997 998 and 999.
1000
Easier way than what?I presume you mean long multiplication of 999 by 999, adding 998 and adding 1.One way:999 = 1000 - 1 ⇒ 999 x 999 + 998 + 1 = (1000 - 1) x (1000 - 1) + 998 + 1= 10002 - 2 x 1000 + 1 + 998 + 1= 1000000 - 2 x 1000 + 1000= 1000000 - 1000= 999000Another way:998 + 1 = 999 ⇒ 999 x 999 + 998 + 1 = 999 x 999 + 999= 999 x (999 + 1)= 999 x 1000= 999000
It is: 999
996 997 998 999
You can solve this problem algebraically: (X) + (X+1) + (X+2) + (X+3) = 3990 4X + 6 = 3990 4X + 6 - 6 = 3990 - 6 4X = 3984 4X/4 = 3984/4 X = 996 Therefore, the 4 numbers are 996, 997, 998, 999 996 + 997 + 998 + 999 = 3990
1001
500.5 Because: 1+2+3+.......998+999+1000 Add 1 to 1000 equaling 1001. This makes a pair. There are 500 more of these so 500 pairs. So 1001x500= 500500 Finally divide it by 1000 because there are 1000 numbers. (1000-1=999+1=1000) Concluding the answer to be 500.5 :)
use < or> to write a true sentence 999 997
When you sum 998 with 1.
1997
500,500