500,500
Easier way than what?I presume you mean long multiplication of 999 by 999, adding 998 and adding 1.One way:999 = 1000 - 1 ⇒ 999 x 999 + 998 + 1 = (1000 - 1) x (1000 - 1) + 998 + 1= 10002 - 2 x 1000 + 1 + 998 + 1= 1000000 - 2 x 1000 + 1000= 1000000 - 1000= 999000Another way:998 + 1 = 999 ⇒ 999 x 999 + 998 + 1 = 999 x 999 + 999= 999 x (999 + 1)= 999 x 1000= 999000
There are 998 of them: 2, 3, 4, 5, ... , 996, 997 998 and 999.
1 + 999 = 1000
When you sum 998 with 1.
There is an equation to find the sum of a list of numbers . It is called the Arithmetic Progression. The equation is S(n) = (n/2)[a + (n-1)d] 4 Where n = number of terms (1000) a = first term (1000) d = difference between terms (1) Hence S(1000) = (1000/2)[1000 + ( 1000 - 1)(1)] S(1000) = 500[ 1000 + 999] S(1000) = 500[1999] S(1000) = 999500 The answer!!!!!
1000 (in base ten) in base 16: 999 + 1 = 99AADDITIONAL ANSWER:In basic Arithmetic 1 + 999 = 1,000
500.5 Because: 1+2+3+.......998+999+1000 Add 1 to 1000 equaling 1001. This makes a pair. There are 500 more of these so 500 pairs. So 1001x500= 500500 Finally divide it by 1000 because there are 1000 numbers. (1000-1=999+1=1000) Concluding the answer to be 500.5 :)
142 999-1= 998 998/7 = 142.5714286 not 143, so 7 goes into 998 142 times evenly. This answer brought to you by the Casio FX-115ES
998
The average(also known as the mean) of the set of numbers 1,2,3,4,5,997,998,999,1000 is 445.4444444Working Out:1+2+3+4+5+997+998+999+1000=40094009/9=445.4444444*Note we divided by 9 because there were a total of 9 numbers in the set.*
All numbers from 1 to 998 precede the number 999.
999 MOD 1000 = 999