42 + 52 = 16 + 25 = 41
(25+26+27+28+29+30+31+32+33+34+35+36+37+38+39+40+41) / 17 => 561/17 => 33 The Answer
The number halfway between 13 and 41 can be found by taking the average of the two numbers. To find the average, you add the two numbers together and divide by 2. In this case, (13 + 41) / 2 = 27. Therefore, the number halfway between 13 and 41 is 27.
41-25 = 16
Find three consecutive positive even integers whose sum is 123 , Answer
The average of the integers 25 and 41 is 33. Average is found by adding up the integers and dividing that number by the number of integers that were added together. So, 25+41=66, then 66/2=33.
It is 33.
66
It is 33.
It is 33.
33
66
It is 41 - 25 = 16
42 + 52 = 16 + 25 = 41
33. ( how i got it 25+41= 66; 66/2= 33)
Since 16 + 25=41, we know the integers are 4 and 5.
41 is between the integers 40 and 42. This can be determined by understanding that integers are whole numbers without any decimal or fractional parts. In this case, 41 is one unit greater than 40 and one unit less than 42 on the number line.