Ah, isn't that just lovely? Let's paint a happy little binary sequence together. Starting with 8, we have 1000, then 1001 for 9, 1010 for 10, 1011 for 11, 1100 for 12, 1101 for 13, 1110 for 14, and finally 1111 for 15. Just like that, we've created a beautiful sequence of numbers that dance across the canvas of our minds.
The binary number 1111 is 15. The digits in a binary number are exponents of 2 rather than 10, so that for a four digit number in binary, the digit places represent 8, 4, 2, 1 instead of increasing values of 10. 1111 = 8+4+2+1 = 15
The next number in the sequence is 15 - the sequence goes x2, +2, -1
An 8 bit binary code is a code that is 8 digits long. It would look like this: 00110010
u15 = u7 + (15-7)*d = 2.33 + 8*(-0.67) = -3.03
The next number in the sequence is 48.
No one on this site will know how do this. It's far too complicated, as for me I think you need to figure out how to do this yourself.
1111 Converting each 1 into their respective values gives: 1 x 8 = 8 1 x 4 = 4 1 x 2 = 2 1 x 1 = 1 8 + 4 + 2 + 1 = 15
1111 (8+4+2+1)
Express it as a sum of powers of 2, thus: 15 = 8 + 4 + 2 + 1. The binary representation has a one for every power of two that is present and 0 when not. So 15, in binary, is 1111.
0000 0000 1111 1000F ( or 15) = 1111 in binary, and 8 = 1000 in binary, so F is 1111 1000
Assuming you start from 0, you need at least 4 bits. 15 in binary: 15 = 8 + 4 + 2 + 1 = 1111₂
A number sequence is not a question. So there can be no "answer".
The binary number 1111 is 15. The digits in a binary number are exponents of 2 rather than 10, so that for a four digit number in binary, the digit places represent 8, 4, 2, 1 instead of increasing values of 10. 1111 = 8+4+2+1 = 15
20
Eight bits (binary digits) together form one byte.
The sum of a geometric sequence is a(1-rn)/(1-r) In this case, a = 8, r = -2 and n=15 So the sum is 8(1-(-2)15)/(1+2) =8(1+32768)/3 =87,384 So the sum of the first 15 terms of the sequence 8, -16, 32, -64.... is 87,384.
8