The binary number 1111 is 15. The digits in a binary number are exponents of 2 rather than 10, so that for a four digit number in binary, the digit places represent 8, 4, 2, 1 instead of increasing values of 10. 1111 = 8+4+2+1 = 15
The next number in the sequence is 15 - the sequence goes x2, +2, -1
An 8 bit binary code is a code that is 8 digits long. It would look like this: 00110010
u15 = u7 + (15-7)*d = 2.33 + 8*(-0.67) = -3.03
The next number in the sequence is 48.
No one on this site will know how do this. It's far too complicated, as for me I think you need to figure out how to do this yourself.
1111 Converting each 1 into their respective values gives: 1 x 8 = 8 1 x 4 = 4 1 x 2 = 2 1 x 1 = 1 8 + 4 + 2 + 1 = 15
1111 (8+4+2+1)
Express it as a sum of powers of 2, thus: 15 = 8 + 4 + 2 + 1. The binary representation has a one for every power of two that is present and 0 when not. So 15, in binary, is 1111.
0000 0000 1111 1000F ( or 15) = 1111 in binary, and 8 = 1000 in binary, so F is 1111 1000
Assuming you start from 0, you need at least 4 bits. 15 in binary: 15 = 8 + 4 + 2 + 1 = 1111₂
A number sequence is not a question. So there can be no "answer".
The binary number 1111 is 15. The digits in a binary number are exponents of 2 rather than 10, so that for a four digit number in binary, the digit places represent 8, 4, 2, 1 instead of increasing values of 10. 1111 = 8+4+2+1 = 15
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Eight bits (binary digits) together form one byte.
The sum of a geometric sequence is a(1-rn)/(1-r) In this case, a = 8, r = -2 and n=15 So the sum is 8(1-(-2)15)/(1+2) =8(1+32768)/3 =87,384 So the sum of the first 15 terms of the sequence 8, -16, 32, -64.... is 87,384.
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