Because the standard cue ball used in American pocket billiards is 2.25 inches in diameter, the circumference is approximately 7.07 inches. You find this answer by using the formula for circumference of a circle given by C= 2 x pi x radius, where pi equals 3.14 and radius is 2.25 divided by 2 or 1.125 inches.
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Circumference of pool ball: 2*pi = 6.283 inches rounded to 3 decimal places
Circumference = 2*38*pi feet
The circumference of a 55 centimeter ball is: 172.8 cm(c = d x Pi)
The circumference of the pool is 24 ft so its radius is 24/(2*pi) = 3.8 ft.Then radius of pool + edging = 3.8 + 2 = 5.8 ft.So circumference around edging = 36.6 feet = 36.6/3 = 12.2 yards.The circumference of the pool is 24 ft so its radius is 24/(2*pi) = 3.8 ft.Then radius of pool + edging = 3.8 + 2 = 5.8 ft.So circumference around edging = 36.6 feet = 36.6/3 = 12.2 yards.The circumference of the pool is 24 ft so its radius is 24/(2*pi) = 3.8 ft.Then radius of pool + edging = 3.8 + 2 = 5.8 ft.So circumference around edging = 36.6 feet = 36.6/3 = 12.2 yards.The circumference of the pool is 24 ft so its radius is 24/(2*pi) = 3.8 ft.Then radius of pool + edging = 3.8 + 2 = 5.8 ft.So circumference around edging = 36.6 feet = 36.6/3 = 12.2 yards.
Circumference of a circle = 2*pi*radius or diameter*pi