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What is the quotient when the polynomial 2x4 minus 9x3 plus 13x2 minus 15x plus 9 is divided by the polynomial x minus 3?
2x^3 - 3x^2 + 4x - 3
What is 4x plus 2?
It's a polynomial of degree 1.
What is the degree of this polynomial 3x to the 2nd power - 4x plus 9?
The highest power of the variable is 2, so it is a second degree polynomial.
What is the degree of the polynomial 2x7 plus 4 - 3x3 plus 5x8 - 4x?
I'm going to assume the polynomial in question is 2x7+(3-2x3)+(5x8-4x) Expanding out the polynomial: 2x7+3-2x3+5x8-4x Order the terms by powers of x: 5x8+2x7-2x3-4x+3 Since 8 is the highest power of x, the degree of the polynomial is 8.
3x2 plus 4x-15 equals 0?
no 3x2=6 then 4x-15= -60 so 6 added with - 60 = -54
What degree is 3x2-4x plus 9 in math?
It is a second degree polynomial.
What is the degree of this polynomial 3x2-4x 9?
It is of the 2nd degree.
What is the degree if this polynomial 3x² - 4x plus 9?
3x² - 4x + 9 is a polynomial of degree 2.
What is the quotient when the polynomial 2x4 minus 9x3 plus 13x2 minus 15x plus 9 is divided by the polynomial x minus 3?
2x^3 - 3x^2 + 4x - 3
What is 4x plus 2?
It's a polynomial of degree 1.
What is the degree of this polynomial 3x to the 2nd power - 4x plus 9?
The highest power of the variable is 2, so it is a second degree polynomial.
What is the degree of the polynomial 2x7 plus 4 - 3x3 plus 5x8 - 4x?
I'm going to assume the polynomial in question is 2x7+(3-2x3)+(5x8-4x) Expanding out the polynomial: 2x7+3-2x3+5x8-4x Order the terms by powers of x: 5x8+2x7-2x3-4x+3 Since 8 is the highest power of x, the degree of the polynomial is 8.
Factor this polynomial completely 3x2 plus 2x - 8?
3x2 + 2x - 8 = 3x2 + 6x - 4x - 8 = 3x(x+2) - 4(x+2) = (3x-4)*(x+2)
Is -4x plus 3y a polynomial?
Yes. -4x is one, and 3y is one. They are combined with a "+" sign, and together they are a polynomial.
3x2 plus 4x-15 equals 0?
no 3x2=6 then 4x-15= -60 so 6 added with - 60 = -54
How many roots does 3x2 plus 4x plus 3 have?
two complex
How many roots 3x2 plus 4x plus 8 have?
No real roots.
