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Assuming you are talking about a rectangular area, the diagonal would be found using the Pythagorean Theorem. 5^2 + 10^2 = d^2, so 125 = d^2, then take square root of both sides.
This means the diagonal is approximately 11.18 feet. It is exactly 5√5 feet.
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What is the area of a square with a circle of a radius of 5 inches?
If the circle is inscribed in the square, the side length of the square is the same as the diameter of the circle which is twice its radius: → area_square = (2 × 5 in)² = 10² sq in = 100 sq in If the circle circumscribes the square, the diagonal of the square is the same as the diameter of the circle; Using Pythagoras the length of the side of the square can be calculated: → diagonal = 2 × 5 in = 10 in → side² + side² = diagonal² → 2 × side² = diagonal² → side² = diagonal² / 2 → side = diagonal / √2 → side = 10 in / √2 → area _square = (10 in / √2)² = 100 sq in / 2 = 50 sq in.
What is the the length of the diagonal of a 10 cm by 15 cm rectangle?
Use Pythagoras: diagonal² = length² + width² → diagonal² = (10 cm)² + (15 cm)² → diagonal = √(10² + 15²) cm = √325 cm = 5 √13 cm ≈ 18 cm
How do you find the area of a rectangle with the diagonal of 13 and a width of 5?
if a rectangle has width of 5 and diagonal with lenght of 13, what is the area of the rectangle? Use Pythagoras' theorem to find the length of the rectangle which will be 12 5*12 = 60 square units
What is the Difference between linear foot and square foot?
A linear foot is distance. A square foot is area. One square foot is the area of some square tiles used on floors. Ten square feet is 1 foot x 10 feet or 2 feet x 5 feet. Don't confuse this with a 10 foot square which is 10 feet by 10 feet which equals 100 square feet.
13. The astronomy observatory pictured below has a diameter of 10 feet. a. What is the area of the floor?
Assuming your picture shows a circular floor, the area of a circle with a radius of 5 feet is approx. 78.54 square feet
What is the area of a rectangle if the width is 3 feet and the diagonal is 5 feet?
12 squft
What is the diagonal of a 5 foot square?
The diagonal of a 5 foot square is about 7.07 feet.
What is the area of the rectangle with the width of a rectangle is 5 feet and the diagonal is 9 feet?
Pythagorean Theorem: a2+b2=c2 c=diagonal, a and b are side lengths for a right triangle (a rectangle is basically two right triangles) 92=52+a2 a2=92-52 a=~7.48 feet 7.48 feet*5 feet = 37.41 feet = the area of the rectangle
What is the area 10 feet long and 5 feet wide?
10*5 = 50 square feet
How many feet in the diameter of a 5 acre square lot?
A square with an area of five acres has a diameter of 466.7 feet and a diagonal length of 660 feet.
What is the surface area of a cylinder that 10 feet high and 5 feet radius?
A cylinder 10 feet high and 5 feet in radius has a surface area of 471.24ft2
What is the area of a rectangle with length 5 feet and width 10 feet?
It is: 5*10 = 50 square feet
The width of a rectangle is 6 feet and the diagonal is 10 feet. What is the area of the rectangle?
Based on a right triangle and the 3, 4, 5 setup, the length of the rectangle is 8 feet, making the area 6 x 8 = 48 square feet.*Compute the length using the formula a2 + b2 = c2(the diagonal is the hypotenuse of the right triangle)62 + b2 = 10236 + b2 = 100b2 = 64 and b = 8
What is area if diagonal of square is 5 root of 2?
Diagonal = 5*sqrt(2) units implies that side = 5 units so that area = 5*5 = 25 square units.
What is the area if one side is 10 ft and the other is 5 ft?
Area = 10*5 = 50 square feet
What is area of a rectangle that has the length of 5 feet and the width of 2 feet?
10 feet squared!
What is the area of a square with a circle of a radius of 5 inches?
If the circle is inscribed in the square, the side length of the square is the same as the diameter of the circle which is twice its radius: → area_square = (2 × 5 in)² = 10² sq in = 100 sq in If the circle circumscribes the square, the diagonal of the square is the same as the diameter of the circle; Using Pythagoras the length of the side of the square can be calculated: → diagonal = 2 × 5 in = 10 in → side² + side² = diagonal² → 2 × side² = diagonal² → side² = diagonal² / 2 → side = diagonal / √2 → side = 10 in / √2 → area _square = (10 in / √2)² = 100 sq in / 2 = 50 sq in.
