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Explain how to find the distance between the points (28-17) and (-15-17) on a coordinate plane?
the first point is x = 28 and y = -17. The second point is x = -15 and y = -17. Since both points have the same y coordinate then the points are on a straight horizontal line and distance is the difference of the x coordinates, or 28 - (-15) = 43
Explain how to find the distance between the points (28 -17) and (-15-17) on a coordinate plane?
To find the distance between any two points on the Cartesian plane use Pythagoras: The distance between (x0, y0) and (x1, y1) is given by: distance = √((x1 - x0)² + (y1 - y0)²) → distance between (28, -17) and (-15, -17) is: distance = √((x1 - x0)² + (y1 - y0)²) = √((-15 - 28)² + (-17 - -17)²) = √((-43)² + (0)) = √1849 = 43 ------------------------ In this case, the y-coordinates are the same (y0 = y1 = -17), so this becomes: distance = √((x1 - x0)² + (y0 - y0)²) = √((x1 - x0)² + 0²) = √((x1 - x0)²) = |x1 - x0| The vertical bars around the expression mean the absolute value of the expression, which is the numerical value of the expression ignoring the sign. distance = |x1 - x0| = |-15 - 28| = |-43| = 43.
What is the number between 13 and 17?
The whole number between 13 and 17 is 15
What is the distance between the points (-7 -13) and (8 -5)?
To find the distance between two points (x0, y0) and (x1, y1) use Pythagoras: distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((8 - -7)² + (-5 - -13)²) → distance = √(15² + 8²) → distance = √289 → distance = 17 units.
What are the prime numbers between 15 and 25?
The prime numbers between 15 and 25 are- 17, 19 and 23.They are: 17, 19 and 23They are: 17 19 and 23
Explain how to find the distance between the points (28-17) and (-15-17) on a coordinate plane?
the first point is x = 28 and y = -17. The second point is x = -15 and y = -17. Since both points have the same y coordinate then the points are on a straight horizontal line and distance is the difference of the x coordinates, or 28 - (-15) = 43
Explain how to find the distance between the points (28 -17) and (-15-17) on a coordinate plane?
To find the distance between any two points on the Cartesian plane use Pythagoras: The distance between (x0, y0) and (x1, y1) is given by: distance = √((x1 - x0)² + (y1 - y0)²) → distance between (28, -17) and (-15, -17) is: distance = √((x1 - x0)² + (y1 - y0)²) = √((-15 - 28)² + (-17 - -17)²) = √((-43)² + (0)) = √1849 = 43 ------------------------ In this case, the y-coordinates are the same (y0 = y1 = -17), so this becomes: distance = √((x1 - x0)² + (y0 - y0)²) = √((x1 - x0)² + 0²) = √((x1 - x0)²) = |x1 - x0| The vertical bars around the expression mean the absolute value of the expression, which is the numerical value of the expression ignoring the sign. distance = |x1 - x0| = |-15 - 28| = |-43| = 43.
What is the distance between the points -4 17 and 11 17 in the xy-plane?
It is the square root of (-4-11)2+(17-17)2 which works out as 15.
What is the slope of the line between 2 5 and 4 17?
Slope = (difference in y coordinate) / (difference in x coordinate) = (17 - 5) / (4 - 2) = 12/2 = 6
What is the number between 13 and 17?
The whole number between 13 and 17 is 15
How long a drive is it from Tucson to Lake Tahoe?
Between 15 and 17 hours, depending on traffic and road conditions. The distance is about 1,002 miles.
What is the distance between the points (-7 -13) and (8 -5)?
To find the distance between two points (x0, y0) and (x1, y1) use Pythagoras: distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((8 - -7)² + (-5 - -13)²) → distance = √(15² + 8²) → distance = √289 → distance = 17 units.
What is the distance between derby and Nottingham?
17 miles
What is the distance between Birmingham and Wolverhampton?
17 miles
What is the distance between perumbavoor to thrikkanarvattom?
17 miles
What is the distance between Toronto and scarborugh?
17 miles
Distance between Manila City Hall and the Elliptical Road in Quezon City?
The distance between the Manila City Hall and the Elliptical Road in Quezon City is 13 to 15 km. The driving time would be approximately 17 minutes.
