It is the square root of (-4-11)2+(17-17)2 which works out as 15.
20
To find the distance between the points (3, -8) and (3, -19), you can use the distance formula, which is (d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}). Substituting the points into the formula: (d = \sqrt{(3 - 3)^2 + (-19 - (-8))^2} = \sqrt{0 + (-11)^2} = \sqrt{121} = 11). Thus, the distance between the points is 11.
Distance2 = (21-9)2 + (16-11)2 = 169 and the square root of this is the distance which is 13 units
To find the distance between the points (5, 35) and (11, 43) in the xy-plane, you can use the distance formula: ( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ). Plugging in the values, we get ( d = \sqrt{(11 - 5)^2 + (43 - 35)^2} = \sqrt{6^2 + 8^2} = \sqrt{36 + 64} = \sqrt{100} = 10 ). Therefore, the distance between the two points is 10 units.
To find the distance between the points (80, 55) and (20, 44), we can use the distance formula: [ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ] Plugging in the coordinates, we get: [ d = \sqrt{(20 - 80)^2 + (44 - 55)^2} = \sqrt{(-60)^2 + (-11)^2} = \sqrt{3600 + 121} = \sqrt{3721} = 61 ] Thus, the distance between the points is 61 units.
20
11 points
If you mean points of (21, 16) and (9, 11) then the distance works out as 13
If you mean points of (21, 16) and (9, 11) then the distance works out as 13
To find the distance between the points (3, -8) and (3, -19), you can use the distance formula, which is (d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}). Substituting the points into the formula: (d = \sqrt{(3 - 3)^2 + (-19 - (-8))^2} = \sqrt{0 + (-11)^2} = \sqrt{121} = 11). Thus, the distance between the points is 11.
10
If you mean points of (1, -2) and (-9, 3) then the distance is about 11 units using the distance formula
Distance2 = (21-9)2 + (16-11)2 = 169 and the square root of this is the distance which is 13 units
To find the distance between the points (5, 35) and (11, 43) in the xy-plane, you can use the distance formula: ( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ). Plugging in the values, we get ( d = \sqrt{(11 - 5)^2 + (43 - 35)^2} = \sqrt{6^2 + 8^2} = \sqrt{36 + 64} = \sqrt{100} = 10 ). Therefore, the distance between the two points is 10 units.
If you mean points of (1, -2) and (-9, 3) then it works out as about 11
To find the distance between the points (80, 55) and (20, 44), we can use the distance formula: [ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ] Plugging in the coordinates, we get: [ d = \sqrt{(20 - 80)^2 + (44 - 55)^2} = \sqrt{(-60)^2 + (-11)^2} = \sqrt{3600 + 121} = \sqrt{3721} = 61 ] Thus, the distance between the points is 61 units.
If you mean endpoints (-1, -3) and (11, -8) then by using the distance formula the length between the points is 13 units