Using Pythagoras: distance = √(change_in_x2 + change_in_y2) = √((5 - -8)2 + (4 - 4)2) = √(132 + 02) = √(132) = 13 units.
The other end point is (8,-10).
The mid point is at the mean average of each of the coordinates: The midpoint between A (6,3) and and B (8,1) is (6+8/2, 3+1/2) = (7, 2)
Using Pythagoras Length AB = √((-8 - 2)² + (4 - -4)²) = √(6² + 8²) = √100 = 10 units.
.8-.15=.65 so this is the distance between them. Half that distance is .325. Now .325 to .15 or subtract it from .8 and we have the number in the middle. .475 is the number exactly in the middle. This might be easier to see with some integers. Take 6 and 8 and we want to know what number is in the middle. Of course we know it is 7. But 8-6 is 2 so that is the distance between them. Now add 1/2 of that, which is 1 to 6 or subtract it from 8 and you have 7. So .325 is the distance between the two numbers, .475 is the number that would be equidistant from both on the number line.
17 units in length
7.62
The x distance is (-2-(-8)) = 6 The y distance is (-1-(-7)) = 6 The point to point distance is from Pythagorean theorem square root of (x squared +y squared) = 8.485
3
1. Draw a coordinate grid. 2. Put the point (-6, 8) on the grid. 3. Notice you can draw a right triangle. (From origin go 6 left. Make a point. Then go 8 up) 5. Use pythagorean theorem to find hypoteneuse. 6. 62 + 82 = r2
If you mean points of (-2, -6) and (-2, 2) then it works out as 8
The Inside - 2005 Point of Origin 1-8 is rated/received certificates of: Netherlands:12
Points: (8, 3) and (8, 6) Distance works out as: 3
Points: (2, 2) and (8, -6) Distance: 10
8
5 centimeters to the right from the point of origin
ER - 1994 Point of Origin 5-18 was released on: USA: 8 April 1999