Best Answer

The distance from the origin {0;0} to {-6;8} is:

SQRT ((X2-X1)2 + (Y2-Y1)2)

SQRT(-62+82) = SQRT (36+64) = SQRT (100) = 10 (Exactly)

Answer:10

Q: What is the distance of point p -6 8 from origin?

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Using Pythagoras: distance = √(change_in_x2 + change_in_y2) = √((5 - -8)2 + (4 - 4)2) = √(132 + 02) = √(132) = 13 units.

The other end point is (8,-10).

The mid point is at the mean average of each of the coordinates: The midpoint between A (6,3) and and B (8,1) is (6+8/2, 3+1/2) = (7, 2)

Using Pythagoras Length AB = √((-8 - 2)² + (4 - -4)²) = √(6² + 8²) = √100 = 10 units.

Time = Distance/Speed = 6/45 hours = 8 minutes.

Related questions

17 units in length

7.62

The x distance is (-2-(-8)) = 6 The y distance is (-1-(-7)) = 6 The point to point distance is from Pythagorean theorem square root of (x squared +y squared) = 8.485

3

1. Draw a coordinate grid. 2. Put the point (-6, 8) on the grid. 3. Notice you can draw a right triangle. (From origin go 6 left. Make a point. Then go 8 up) 5. Use pythagorean theorem to find hypoteneuse. 6. 62 + 82 = r2

If you mean points of (-2, -6) and (-2, 2) then it works out as 8

Points: (8, 3) and (8, 6) Distance works out as: 3

The Inside - 2005 Point of Origin 1-8 is rated/received certificates of: Netherlands:12

Points: (2, 2) and (8, -6) Distance: 10

8

5 centimeters to the right from the point of origin

Points: (6, 5) and (-3, -8) Distance: 15.81 to the nearest hundredth