The distance from the origin {0;0} to {-6;8} is:
SQRT ((X2-X1)2 + (Y2-Y1)2)
SQRT(-62+82) = SQRT (36+64) = SQRT (100) = 10 (Exactly)
Answer:10
Using Pythagoras: distance = √(change_in_x2 + change_in_y2) = √((5 - -8)2 + (4 - 4)2) = √(132 + 02) = √(132) = 13 units.
The other end point is (8,-10).
The mid point is at the mean average of each of the coordinates: The midpoint between A (6,3) and and B (8,1) is (6+8/2, 3+1/2) = (7, 2)
Using Pythagoras Length AB = √((-8 - 2)² + (4 - -4)²) = √(6² + 8²) = √100 = 10 units.
Time = Distance/Speed = 6/45 hours = 8 minutes.
17 units in length
7.62
The x distance is (-2-(-8)) = 6 The y distance is (-1-(-7)) = 6 The point to point distance is from Pythagorean theorem square root of (x squared +y squared) = 8.485
3
1. Draw a coordinate grid. 2. Put the point (-6, 8) on the grid. 3. Notice you can draw a right triangle. (From origin go 6 left. Make a point. Then go 8 up) 5. Use pythagorean theorem to find hypoteneuse. 6. 62 + 82 = r2
If you mean points of (-2, -6) and (-2, 2) then it works out as 8
Points: (8, 3) and (8, 6) Distance works out as: 3
The Inside - 2005 Point of Origin 1-8 is rated/received certificates of: Netherlands:12
Points: (2, 2) and (8, -6) Distance: 10
8
5 centimeters to the right from the point of origin
Points: (6, 5) and (-3, -8) Distance: 15.81 to the nearest hundredth