The distance, expressed in inches, is
(1.2) x (the particle's average speed, in feet per minute) .
2
it's answer "c"
97 miles = 97 x 5280 = 512160 feet traversed in 3600 seconds. Hence 60 feet would be traversed in (3600/512160) x 60 = 60/512160 = 0.00011715 seconds
To find the average speed between time=0 and time=2, divide the distance traveled by the time (in this case 2 seconds).
The answer will depend on its acceleration.
The average speed is one fifth of the distance that she travels from the third to the eighth second.
it's answer "c"
97 miles = 97 x 5280 = 512160 feet traversed in 3600 seconds. Hence 60 feet would be traversed in (3600/512160) x 60 = 60/512160 = 0.00011715 seconds
speed= distance per seconds & torque= revolution per seconds
000000035 seconds
i
2 seconds is the safe distance.
There is not enough information to answer this - it could be anything, depending on how the particle moves.
8 seconds
your line-of-sight is greater than 30 seconds ahead
To find the average speed between time=0 and time=2, divide the distance traveled by the time (in this case 2 seconds).
Safe distance is 2 seconds, or 4 car lengths. More if snow is on the ground or its raining.
There is no general conversion between time and distance. For speed problems, use the formula distance = speed x time.