Add the digits of the number together and if the sum is divisible by 3 then the original number is divisible by 3.
The test can be applied to the sum and so the summation can be repeated until a single digit remains; if this digit is 3, 6 or 9 then the original number is divisible by 3.
3 and 9. And they divide into 123456789 whether or not you use divisibility rules!
No.
there is a divisibility for 24 the rule is you can divide 24 as 6 and 4 i think
The divisibility rule of 3 is that you add the digits together and then if the number you come up with is divisible by 3, then the number itself is divisible by 3. In this instance, 5 + 8 + 5 = 18/3 = 6, therefore, 585 is divisible by 3.
If the sum of the digits is divisible by 3, the number is also.
It is divisibility by 3 and divisibility by 5.Divisibility by 3: the digital root of an integer is obtained by adding together all the digits in the integer, with the process repeated if required. If the final result is 3, 6 or 9, then the integer is divisible by 3.Divisibility by 5: the integer ends in 0 or 5.
It is 3 6 9
It is: 5034/3 = 1678
It is divisible by 3 (3*125 = 375).
678 is divisible by 3.
The divisibility rule for 3 is add up the digits and check for divisibility. 7+2+4 = 13.13 is not evenly divisible by 3 so 724 is not divisibleby 3.
Not equally. The decimal answer is 30.66666
3 - 31
3 and 9. And they divide into 123456789 whether or not you use divisibility rules!
The number 36940 is divisible by 12 because it meets the criteria for divisibility by both 3 and 4. To check for divisibility by 3, we sum the digits (3 + 6 + 9 + 4 + 0 = 22), and since 22 is not divisible by 3, we need to reassess. However, for divisibility by 4, the last two digits (40) are divisible by 4. Since it fails the divisibility test for 3, 36940 is not divisible by 12.
The multiples of 9 are: 1 and 9 3 and 3
the # needs to be divisible by 2 and 3.