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Q: What is the equation of a circle with center 8 6 and radius 5?

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If you mean: (x+9)^2 + (y+5)^2 = 64 Then the center of the circle is at (-9,-5) and the radius is 8

The equation of a circle can be written in the form (x-h)2 + (y - k)2 = r2, where r is the radius, and (h,k) is the center. So for your example, the equation would be: (x- 5)2 + (y - 3)2 = 72

A circle with centre (X, Y) and radius R has an equation of the form: (x - X)² + (y - Y)² = R² → circle centre (-5, 2), radius 5 has equation: (x - -5)² + (y - 2)² = 5² → (x + 5)² + (y - 2)² = 5² This can be expanded and simplified: → x² + 10x + 25 + y² -4y + 4 = 25 → x² + 10x + y² - 4y + 4 = 0

A circle with a radius of 5 units has an area of 78.54 square units.

The radius of the circle is the length between the middle of the circle and any of the sides. It is also half the lenght of the diameter.

Related questions

center 5,-3 radius 4

The equation is: (x+1)^2 +(y+5)^2 = 36

If you mean: (x+9)^2 + (y+5)^2 = 64 Then the center of the circle is at (-9,-5) and the radius is 8

(x - 9)2 + (y + 5)2 = 16

(x + 3)2 + (y + 5)2 = 36

(x+3)2 + (y-5)2 = 9

(x - 3)2 + (y + 5)2 = 16

(x + 1)2 + (y + 5)2 = 36

It is: (x+3)^2 + (y+5)^2 = 36

It is (x - 1)^2 + (y - 1)^2 = 5^2

The equation of a circle can be written in the form (x-h)2 + (y - k)2 = r2, where r is the radius, and (h,k) is the center. So for your example, the equation would be: (x- 5)2 + (y - 3)2 = 72

Centre = (-9, -5)Radius = 8

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