It is: (x+3)^2 + (y+5)^2 = 36
(x-3)^2-(y-3)^2=(12)^2
(x + 6)2 + (y - 9)2 = 3 The general formula for the equation of a circle is: (x + 'horizontal shift')2 + (y + 'vertical shift')2 = radius
It is: (x-3)^2 +(y -2)^2 = 18.49
If you mean: (x+5)^2 + (y+3)^2 = 16 Then its center is at (-5, -3) and its radius is 4
Equation of circle: x^2 +y^2 -4x -6y -3 = 0 Completing the squares: (x-2)^2 +(y-3)^2 = 16 square units Therefore center of circle is at (2, 3) and its radius is 4 units
this is impossible
Centre of the circle: (3, 8) Radius of the circle: 2 Cartesian equation of the circle: (x-3)^2 + (y-8)^2 = 4
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Center of circle: (6, 8) Radius of circle: 3
center 5,-3 radius 4
This makes no sence
If you mean a circle center at (3, 1) and a radius of 2 then the equation of the circle is (x-3)^2 +(y-1)^2 = 4
The equation of a circle with center (2, -3) and radius 3 can be written as (x - 2)^2 + (y + 3)^2 = 3^2.
If you mean a circle center at (3, 1) and a radius of 2 then the equation of the circle is (x-3)^2 +(y-1)^2 = 4
(x-3)2+y2=144
I think it is center: (-4, 3) ; radius: 2 Apex:)
(x+3)2 + (y-5)2 = 9