Parallel lines have the same slope. So if you put the equation 4x + y -1 = 0 into the slope-intercept form of the equation of a line (y = mx + b), you can read the slope, m, from it. Rearranging that equation gives: y = -4x + 1. The slope of both lines is -4. If the new line passes through the (x, y) point (1, 2), you can use the point-slope form of the equation of a line and plug in the values to find the equation of the new line:
y - y1 = m(x - x1)
y - 2 = -4(x - 1)
y - 2 = -4x + 4
y = -4x + 6
y = 3x - 3
If the slope of the given equation is 1/5 then the slope of the parallel equation will be the same which works out as: y-8 = 1/5(x-3) => y = 1/5x+7.4
If you mean: y = 3x-4 then the parallel equation is y = 3x-14 because they both will have the same slope but different y intercepts
It passes through Quadrants II and IV. It also passes through the origin ... the point where the 'x' and 'y' axes cross. At that point, it's in all four quadrants.
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Yes, it is a linear equation with no slope. The graph is a straight line (parallel to the x-axis) that passes through the y-axis, at {0,-3}
y -4 = 3(x-3)y = 3x -5
The equation is x = -7.
The parallel equation will have the same slope but with a different y intercept
The equation in point slope of the line which passes through -2 -3 and is parallel to 3x plus 2y 10 is y=-1.5x.
You get a straight line (parallel to the x-axis) that passes through only the y-axis, and it crosses the y-axis at (0,3)
If you mean y = -4x+1 and (2, 1) then the parallel equation is y = -4x+9
If you mean y = -65x-4 then the parallel equation is y = -65x-66
Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4
Answer this question… y = 2
It is: y = 6 and is parallel to the x axis
i dont knows