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What is the equation of the line that passes through the point -7-3 and is parallel to -5x plus 8y equals 27?
Put the equation of the given line into slope-intercept form. The slope is then the coefficient of x.
-5x + 8y = 27.
8y = 5x + 27
y = 5/8 x + 33/8.........so the slope of a parallel line is the same i.e. 5/8
Now use the standard slope-intercept equation , y = mx + c, where m is the slope and c is the y-intercept. Substituting the ordered pair values for x and y, and as m is known - this gives, -3 = 5/8(-7) + c : -3 = -43/8 + c : c = 13/8
The equation of the parallel line is thus, y = 5/8x + 13/8
and multiplying throughout by 8 produces an equivalent equation, 8y = 5x + 11
What else can I help you with?
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2
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Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4
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