Divide the sum of the three consecutive odd integers by 3: -273 /3 = -91. The smallest of these integers will be two less than -91 and the largest will be two more than -91, so the three consecutive odd integers will be -89, -91, and -93.
Sum of divisors = 91.
it would be a common sum of 91+8 2+7 3+6 4+5
45 + 46 = 91.Suck on it, trebek!
A reasonable estimate of the sum of 78 and 119 is 197.
3
3 + 88 = 91
3 + 5 + 83
It is 61: you do not need to estimate a sum as simple as that!
The estimate would be 9.3333 or 91/3
Divide the sum of the three consecutive odd integers by 3: -273 /3 = -91. The smallest of these integers will be two less than -91 and the largest will be two more than -91, so the three consecutive odd integers will be -89, -91, and -93.
The answer is -30.
Sum of divisors = 91.
87,89,91.....87+89+91=267
No, 91 is Not a multiple of 3.An easy way to determine if a number is a multiple or divisible by 3 is to add up all itsdigits and see if the sum is divisible by three.For example: 321 , 3 + 2 + 1, Therefore 321 is divisible by 3 or a multiple of 3.Unlike the number 131, 1 + 3 + 1, whose digits sum up to 5, which isn't divisible by 3.So therefore, 91 is 9+1 Therefore 91 is not a multiple of 3.Hope we helped!
The two different perfect cubes whose sum is closest to 99 without exceeding 99 are 64 and 27 (4^3 and 3^3). Their sum is 91.
it would be a common sum of 91+8 2+7 3+6 4+5