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What is the exact value of cos theta if csc theta -4 with theta in quadrant III?
Wiki User
∙ 7y ago
csc θ = 1/sin θ
→ sin θ = -1/4
cos² θ + sin² θ = 1
→ cos θ = ± √(1 - sin² θ) = ± √(1 - ¼²) = ± √(1- 1/16) = ± √(15/16) = ± (√15)/4
In Quadrant III both cos and sin are negative
→ cos θ= -(√15)/4
Wiki User
∙ 7y ago
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