The GCF is a^2b
4 to the second power
3m(2m + 5)
The greatest common factor (GCF) of 15ab and 5b2 is 5b.
2a to the second power. If you combine the like terms, (a to the second power + a to the second power), it would be the same as 2a to the second power.
2 to the second power is 4, which isn't a factor of 54. 3 to the second power is 9, which is a factor of 54 but isn't prime. 4 divided by 9 is 4/9, which isn't prime and isn't a factor of 54.
3x
The GCF is a^2b
4 to the second power
2 times 3 to the second power equals to 2x9 or 18 2 to the second power times 3 equals to 4x3 or 12 therefore the least common factor is 2.
(c + d)(c + d)
-8
The only prime factor of 49 is seven (7).
Since 14abc is a factor of 28a2b2c3, it is automatically the GCF of this problem.
a3x2 - 216x2 factors to x2(a - 6)(a2 + 6a + 36)
3x
3m(2m + 5)