102
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We can eliminate the prime numbers. Since they have only one prime factor apiece, they don't need a tree.
2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97
The next set has only two prime factors apiece, which would make only one branch, so I've listed them as a prime factor pair.
4: 2, 2
6: 2, 3
9: 3, 3
10: 2, 5
14: 2, 7
15: 3, 5
21: 3, 7
22: 2, 11
25: 5, 5
26: 2, 13
33: 3, 11
34: 2, 17
35: 5, 7
38: 2, 19
39: 3, 13
46: 2, 23
49: 7, 7
51: 3, 17
55: 5, 11
57: 3, 19
58: 2, 29
62: 2, 31
65: 5, 13
69: 3, 23
74: 2, 37
77: 7, 11
82: 2, 41
85: 5, 17
86: 2, 43
87: 3, 29
91: 7, 13
93: 3, 31
94: 2, 47
95: 5, 19
That leaves 8, 12, 16, 18, 20, 24, 27, 28, 30, 32, 36, 40, 42, 44, 45, 48, 50, 52, 54, 56, 60, 63, 64, 66, 68, 70, 72, 75, 76, 78, 80, 81, 84, 88, 90, 92, 96, 98, 99 and 100 which have all been answered individually in other questions. Happy hunting.
Factor tree of 40: 40 20,2 10,2,2 5,2,2,2
Here is a factor tree of eight: 8 / \ 4 2 / \ 2 2
873 x 29Since both 3 and 29 are prime numbers, the factor tree is complete.
To find the factor tree for 193, you start by determining the prime factors of 193. Since 193 is a prime number itself, the factor tree for 193 would simply consist of the number 193 at the top, as it cannot be broken down further into smaller prime factors. Therefore, the factor tree for 193 would just be a single branch with 193 as the prime factor.
2100
The greatest common factor of 1,134 and 2,100 is 42.
The greatest common factor of 330 and 2,100 is 30.
IT IS PRIME there is no factor tree
Factor tree of 204
factor tree of 216
2100
The factor tree of 50:5025,25,5,25025,25,5,2
21
83 is prime. No tree.
The factor tree of 29 would consist of only the number 29 itself, as it is a prime number. Prime numbers have only two factors: 1 and the number itself. Therefore, the factor tree for 29 would simply show 29 at the top with no further branches or factors.
The prime factor tree of 280 is:140,270,2,235,2,2,27,5,2,2,2
Factor Tree of 20: ........20 ......../ \ .......4 5 ....../ \ .....2 2