4x^2 + 32x + 64 =
4(x^2 + 8x + 16) =
4(x + 4)^2 =
4(x + 4)(x + 4)
64
(2x - 7)(2x - 9)
4x2 + 12x + 5 = (2x + 1)(2x + 5).
64
-4x2 + 11x - 6 factors to: (-4x + 3) (x - 2)
2(x + 1)(2x + 1)
4x2(x2-7x+10) 4x2(x-2)(x-5)
2x2(2x - 1)(2x + 1)(4x2 + 1)
4(x^2 + 8x + 160)
false, in order to be one 8 would have to be a square number which it is not. So the constant term in the trinomial would need to be 4, 9, 16 etc.
-4x2 - 32x + x + 8 = 8x2 - 56x : simplify and group the various terms-32x + 56x + x + 8 = 8x2 + 4x225x + 8 = 12x2 : Now present this as a standard quadratic equation.12x2 - 25x - 8 = 0 : Solving for the roots of a quadratic equation gives :-x = [25 ± √(252 + 4x12x8)] ÷ 2x12 = [25 ± √1009] ÷ 24 = [25 ± 31.765] ÷ 24x = 56.765/24 = 2.365 and x = -6.765/24 = -0.282x = 2.365 and -0.282
Divide all terms by 4:- x2+7x+12 = (x+3)(x+4) when factored