How about: 4*5 = 20 as one example
it is 1 and 20, 10 and 2, 5 and 4
Substitute the value for y given by the second equation into the first equation to result in 3x - 15 = x2 - x -20. Subtract (3x - 15) from both sides and exchange sides to yield x2 - 4x - 5 = 0. This can be factored into (x - 5)(x + 1) = 0, which is true when x equals either 5 or -1. If x = 5, y = 0 and if x = -1, then y = -18. Therefore, either 5,0 or -1,-18 is an ordered pair solution to the given equation system.
Twenty Five, 20+5, and (2x10)+(5x1).
20
1x20 2x10 4x5
How about: 4*5 = 20 as one example
It's obvious. Just add 10+10. And that equals 20. It is the same as 10x2=20.
No, they are not equivalent. 2x10 = 20 and 5x25 = 125.
No 2x10=20 and 2x11=22. They are not equal
x=10 y=5 2x10=20 5x5=25 20 + 25 =45
20
It isn't 2X10 = 20, 2X11 = 22
5x=4y=-20 x=-4 y=-5 (-4,-5) is the ordered pair
20 = 1 x 20, 2 x 10, 4 x 5, 5 x 4, 10 x 2, 20 x 1
2x10, 5x4
1x20 2x10 5x4