7 x m = 7m
2 x 7 x m = 14m
To find the greatest common factor (GCF) of 14m^2 and 21m, we first need to factor each term. The factors of 14m^2 are 1, 2, 7, 14, m, and m. The factors of 21m are 1, 3, 7, 21, m, and 1. The common factors between the two terms are 1, 7, and m. Therefore, the greatest common factor of 14m^2 and 21m is 7m.
The GCF is m
7m and 18m2 1m is the GCF
7m
7m
Since 14m - 42 is a multiple of 7m - 21, it is automatically the LCM of this problem.
To find the greatest common factor (GCF) of 14m^2 and 21m, we first need to factor each term. The factors of 14m^2 are 1, 2, 7, 14, m, and m. The factors of 21m are 1, 3, 7, 21, m, and 1. The common factors between the two terms are 1, 7, and m. Therefore, the greatest common factor of 14m^2 and 21m is 7m.
The GCF is 7m.
7 - 14m
GCF(28, 21) = 7 Steps: Prime factorization of the numbers: 28 = 2 × 2 × 7 21 = 3 × 7 GCF(28, 21) = 7
If one term is a factor of the other, it is automatically the GCF. 7m is a factor of 14m and the GCF of this problem.
7x8=56 ANSWER-56
Yes
Find the area of a trapeziod
-5(7m + 9) -7m
The GCF is m
If it's the diameter of a circle then divide it by two