1996.50
If it is compounded annually, then: F = P*(1 + i)^t {F is final value, P is present value, and i is interest rate, t is time}.So if it triples, F/P = 3, and 12 years: t = 12, so we have 3 = (1 + i)^12, solve for i using logarithms (any base log will do, but I'll use base 10):log(3) = log((1+i)^12) = 12*log(1+i)(log(3))/12 = log(1+i).Now take 10 raised to both sides: 10^((log(3))/12) = 10^log(1+i) = 1 + ii = 10^((log(3))/12) - 1 = 0.095873So a rate of 9.5873 % (compounded annually) will triple the investment in 12 years.
Use Compound interest formula I(n) =I(o)[1 + r/100]^n Where I(n) is final amount (4150) I(o) is initial amount (2300) r is rate percent = 6% n is the number of years. ( to be found) Substitute 4150 = 2300 [ 1 + 6/100]^n 4150 = 2300 [ 1.06]^n 1.06^n = 4150/2300 1.06^n = 1.804347826 Take logs to base '10' ( 'log' on the calculator) . log 1.06^n = log 1.804347826 nlog1.06 = log 1.804347826 n(0.025305865 =0.25632026 n = 0.25632026 / 0.025305865 n = 10.12888743 yrs. n ~ 10.125 = 10 1/8 yrs.
If you're simply adding five percent onto the value at the end of each of the three years - the final value would be 578.8125
most final
It is infinity
It is 52936.72
The final amount is $1,647.01
Trial balance
unadjusted will not have your final entries for that period. some of those entries may be accrued revenues or expenses, depreciation, and balancing entries. the adjusted balance is your final balance after all adjustments are made.
balance sheet current liabilites
final statements are trading account,profit and loss account,balance sheet.
Smart and Final cash card is the same as using cash. It's got a balance on it and you can use it to make purchases until the balance runs out. It must be used at Smart and Final stores.
the final result influence the grey colour
yes
750 invested for 10 years at 10% pa would be 1,945
If the balance of accounts payable has increased on the final balance sheet, it means that the company has more creditors to pay and might be struggling with its finances.
Using the compound interest formula A = P(1 + r/n)^(nt), where A is the final amount, P is the principal amount, r is the interest rate, n is the number of times interest is compounded per year, and t is the number of years, we can solve for t when A = 4000, P = 2000, r = 0.06, and n = 1. Plugging these values in, we get: 4000 = 2000(1 + 0.06/1)^(1t) 2 = (1 + 0.06/1)^(1t) 2 = (1.06)^t Taking the logarithm of both sides, we can solve for t: log 2 = t log 1.06 t = log 2 / log 1.06 Using a calculator, we find that t is approximately 11.90. Therefore, it would take approximately 12 years to double the initial amount of 2000 at a 6 percent interest rate compounded annually.