Use Compound interest formula
I(n) =I(o)[1 + r/100]^n
Where
I(n) is final amount (4150)
I(o) is initial amount (2300)
r is rate percent = 6%
n is the number of years. ( to be found)
Substitute
4150 = 2300 [ 1 + 6/100]^n
4150 = 2300 [ 1.06]^n
1.06^n = 4150/2300
1.06^n = 1.804347826
Take logs to base '10' ( 'log' on the calculator) .
log 1.06^n = log 1.804347826
nlog1.06 = log 1.804347826
n(0.025305865 =0.25632026
n = 0.25632026 / 0.025305865
n = 10.12888743 yrs.
n ~ 10.125 = 10 1/8 yrs.
1996.50
With compound interest - the balance after 7 years would be 26336.18
An annual rate of 6.4% compounded quarterly means 1.6% (6.4/4) every 3 months (12/4). A period of 7 years is equivalent to 28 (7 x 4) compounding periods. Let say that the account balance is N dollars, so N = 3,000(1.016)^28 (100% + 1.6% = 1.016) N = $4,678.914
Well, honey, if Taylor's account balance changed by $13 on the day his bank paid interest and he wrote a check for $18, then he must have earned $31 in interest. It's simple math, darling. Just add the check amount to the change in the account balance, and there you have it.
463.72
8 percent compounded quarterly is equivalent to approx 36% annually. At that rate, after 3 years the ending balance would be 1762.72 approx.
The final amount is $1,647.01
If compounded, interest = 81.244 and balance = 456.245 If not compounded, interest = 75 and balance = 450
The question doesn't tell us the compounding interval ... i.e., how often theinterest is compounded. It does make a difference. Shorter intervals makethe account balance grow faster.We must assume that the interest is compounded annually ... once a year,at the end of the year.1,400 x (1.055)3 = 1,643.94 (rounded)at the end of the 3rd year.
At the end of the first year, the balance in the account is: 5000(1+.0638). At the end of the second year, the balance in the account is: 5000(1+.0638)(1+.0638). At the end of the third year, the balance in the account is: 5000(1+.0638)(1+.0638)(1+.0638). At the end of the t year, the balance in the account is: 5000(1+.0638)^t. So, at the end of the tenth year, the balance in the account is 5000(1+.0638)^10 = 9,280.47. $5,000 is your principal, and the remaining ($9,280.47 - $5,000) = $4,280.47 is the interest.
The interest on a business savings account is compounded daily using a 365-day year (366 days each leap year) and calculated on the collected balance.
1996.50
Compound interest is interest that is paid on both the original principal balance and interest earned. For example, a $100 savings account with a 5% rate of interest compounded annually would have a balance of $105 at the end of year one. At the end of year two the account would earn interest income on the entire account balance of $105 and the interest payment would amount to $5.25 at which point the saver would have an account balance of $110.25. The extra 25 cents of income in year two represents interest on the previous year's interest. Savings can be compounded on different dates including annual, monthly, daily, or continuously. The compounding date represents the date that the savings account balance is updated. The difference between daily or monthly compounding does not result in materially different account balances at the end of the compounding period. For example, a $10,000 savings account compounded at 5% monthly would be worth $44,677 at the end of 30 years compared to an account balance of $44,812 when compounded daily.
No. If the account is earning interest the current amount should be greater than the initial deposit.
It would be 259.0875 so, I would guess most banks would round that DOWN to 259.08 rather than up.
Per annum compound interest formula: fv = pv(1+r)^t Where: fv = future value pv = present (initial) value r = interest rate t = time period Thus, fv = 1000*(1+0.07)^5 = 1000*1.4025517307 = $1402.55
29.86