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5x7=35

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Q: What is the first even multiple of 7 with a three in it?
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What number has three digits is less than 140 has 7 for a factor is even and the sum of the three digits is less than 9?

The three digit number satisfying the requirements is 112. The three digit number must be greater than or equal to 100 and less than 140. To have 7 as a factor it must be a multiple of 7 To be even, it must be an even multiple of 7. The first even multiple of 7 greater than or equal to 100 is: 100 ÷ 7 = 14 r 2 → first even multiple is 16 × 7 = 112 The last even multiples of 7 less than 140 is: 140 ÷ 7 = 20 → last even multiple is 18 × 7 = 126 The sum of its digits must be less than 9: 112 → 1 + 1 + 2 = 4 126 → 1 + 2 + 6 = 9 → only 112 fits all the criteria.


First common multiple of 5 and 7 that is even?

It is 70


The first common multiple of 5 and 7 that is even?

70


What are the first three numbers with only even multiples?

Every number has 1 as a multiple. 1*100 = 100 1*7 = 7 As 1 is an odd number there are no numbers with only even multiples.


Why 35 and 7 are the only three consecutive odd prime numbers?

If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.


What is the first common multiple of 5 and 7 that is even?

35 5X7 = 35


What three digit number is a multiple of 7?

105 is a multiple of 7


The sum of three consecutive even integers is -7Find the 3 integers?

There is no solution. The sum of multiple even integers will always be even, and -7 is odd.


Is 92 a multiple of 7?

No, 92 is not an even multiple of 7 (92/7= 13.1428571).


What is this number multiple of 4 an even number a multiple of 7 and not a multiple of 6?

It could be: 4*7 = 28


What are the three consecutive even inters that ad up to 176?

There are no three consecutive even integers that add up to 176.Let the three consecutive even integers be (2n-2), 2n & (2n+2). Then their sum is:(2n-2) + 2n + (2n+2) = 6n⇒ the total must be a multiple of 6.To be a multiple of 6 the number must be an even multiple of 3; for 176:It is even;1 + 7 + 6 = 14; 1 + 4 = 5 which has a remainder of 2 when divided by 3, so 176 is not a multiple of 3.Thus 176 is not a multiple of 6 and so cannot be the sum of three consecutive even integers.


What are the first 5 multiple of 7?

There are no first 5 multiple. Multiple is singular.