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A circle with centre (X, Y) and radius R has an equation of the form:
(x - X)² + (y - Y)² = R²
→ circle centre (-5, 2), radius 5 has equation:
(x - -5)² + (y - 2)² = 5²
→ (x + 5)² + (y - 2)² = 5²
This can be expanded and simplified:
→ x² + 10x + 25 + y² -4y + 4 = 25
→ x² + 10x + y² - 4y + 4 = 0
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What is the formula for the diameter or a circle?
If you are given the radius of the circle, you can use the formula: diameter = 2*radius If you are given the circumference of the circle, you can use the formula: diameter = circumference/pi
What is the centre of a circle called?
The Origin ( or just "origin") * * * * * That is not generally true. The general formula for a circle, in the Cartesian plane, is of the form (x-a)2 + (y-b)2 = r2 where the coordinates of the centre are (a,b) and the radius is r. It is only if both a and b are 0 that the centre is the origin.
If the diameter of a circle is 3 cm what is the radius?
The radius is 1.5. The formula to get the radius is Diameter/2.
What is the radius of the center circle?
Equation of a circle: (x-h)^2+(y-h)^2=r^2 k is the x-coordinate for the centre, h is the y-coordinate for the centre r=raduis if the equation is x^2+y^2=r^2, the centre of the circle is at (0,0)
Why is half the diameter the radius?
A radius is a straight line from the circumference (boundary) of a circle to the centre. A diameter is a straight line that goes from the circumference to the centre and then continues until it reaches the circumference of the other side. In a circle, all points on the circumference are the same distance from the centre. As a result, the second part of the diameter is the same as the first. In other words, diameter = radius + radius = 2*radius.
Write the equation for a circle centered at the origin with a radius of 14?
Formula for a circle with centre (xo, yo) and radius r is: (x - xo)2 + (y - yo)2 = r2 Circle centre (0, 0) and radius 14: (x - 0)2 + (y - 0)2 = 142 x2 + y2 = 196
What is the radii of a circle?
The radius(radii is the plural) of the circle is half the distance of circle's diameter. The formula is r=(1/2)diameter.
What is the centre and radius of a circle passing through the points of 5 5 and 8 5 and 5 1 on the Cartesian plane?
Using the formula of x^2 +2gx +y^2 +2fy +c = 0 it works out that the centre of the circle is at (6.5, 3) and its radius is 2.5 units in length. Alternatively plot the points on the Cartesian plane to find the centre and radius of the circle.
Formula for radius of circle?
radius = diameter/2
Formula for radius of a circle?
radius = diameter/2.
How do you find the equation of a circle?
A circle is the locus of all points equidistant from a fixed point on the plane. The fixed point is called the centre of the circle and the equal distance is called the radius of the circle. We can derive the equation of the circle from the distance formula. Let O be the centre of the circle and r be the radius of the circle. Here the centre = Origin = (0, 0) and the radius = r units. The distance r = sqrt ((x-0)2 + (y-0)2) r = sqrt (x2 + y2) Squaring both the sides, we get x2 + y2 = r2 This is the equation of the circle with centre as Origin. If the centre point is some (h, k), then use the distance formula to find the radius r. The distance r = sqrt ((x-h)2 + (y-k)2) Squaring both sides, we get (x-h)2 + (y-k)2 = r2. This is the equation of the circle with centre as the point (h, k).
What equation represents the graph of a circle?
Equation of a circle when its centre is at (0, 0): x^2 + y^2 = radius^2 Equation of a circle when its centre is at (a, b): (x-a)^2 + (y-b)^2 = radius^2
What is the equation of a circle with center 1and 5 and radius 2?
A circle with centre (xo, yo) and radius r has formula: (x - xo)2 + (y - yo)2 = r2 For circle with centre (1, 5) and radius 2 this is: (x - 1)2 + (y - 5)2 = 22 x2 - 2x + 1 +y2 - 10y + 25 = 4 x2 - 2x + y2 - 10y + 22 = 0
How do get the radius of a circle?
The radius of a circle is calculated by measuring the distance from the centre of the circle to any point (In a straight line) of the outside of the circle. (2 or 2 pi r) :)
What is the centre and radius of a circle enscribed through the points of 6 2 and 8 -2 and 0 2 on the Cartesian plane?
It works out that the circle's centre is at (3, -2) and its radius is 5 on the Cartesian plane.
What is the centre and radius of a circle that passes through the points of 2 0 and 3 1 and -6 10 on the Cartesian plane?
The equation of the circle works out as: (x+2)^2 + (y-5)^2 = 41 The circle's centre is at: (-2, 5) Its radius is the square root of 41
What is the formula for a circle radius r?
Area of a circle = pi*radius2 Circumference of a circle = 2*pi*radius or diameter*pi Diameter of a circle = 2*radius
