d = -(1/2)g*t^2
v = - g*(squareroot(2(d/g)))
wrong the real formula is:
h=-16t^2+s
h= ending height usually 0"
t=time
s= starting height
(example) 0=-16t^2+256
-256 -256
-256=-16t^2
__________
-16
16=t^2
t=4 seconds
They're both the same formula, they are just transposed. The ending height is always zero since you want the intermittent distance and time of that distance.
d = -(1/2)g*t^2 =-(1/2)(32)*t^2=-16*(t^2)
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The time it takes to fall 50,000 feet can be calculated using the formula for free fall time: time = √(2h/g), where h is the height (50,000 feet in this case) and g is the acceleration due to gravity (approximately 9.81 m/s^2). Converting 50,000 feet to meters (approximately 15,240 meters), the calculation would yield a free fall time of approximately 55 seconds. This calculation assumes no air resistance and a vacuum-like environment.
A - 9.8m/s2
56
To calculate the vertical fall over a horizontal distance at a given angle, you can use trigonometry. In this case, the fall at 2 degrees over 6 meters can be calculated using the formula: vertical fall = horizontal distance * tan(angle). Plugging in the values, the vertical fall would be approximately 0.21 meters, or 21 centimeters.
Technically not real free-fall, but close enough to put the point across: -- jumping or diving from the high board at the pool -- the first several seconds of sky-diving -- the 'vomit comet' aircraft that flies parabolic arcs and gives its passengers, such as astronauts in training, several seconds of weightlessness.