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To calculate the vertical fall over a horizontal distance at a given angle, you can use trigonometry. In this case, the fall at 2 degrees over 6 meters can be calculated using the formula: vertical fall = horizontal distance * tan(angle). Plugging in the values, the vertical fall would be approximately 0.21 meters, or 21 centimeters.
What else can I help you with?
How much fall in a 1 degree roof over 10 meter?
10*sin(1) metres = 0.175 metres = 17.5 cm.
How much fall in 10 degrees over 1 metre?
160mm
How much fall in a 2 degree foor over 3.9 mts?
To find the slope or fall of a ball or other object that is at an angle of 2 degrees for over 3.9 minutes, you will need several factors. You will need the distance or length of the slope and the speed of the ball at its peak movement.
How much fall in a 3 degree roof over 7 meter?
30cm
How much fall in a 3 degree roof over 1 meter?
3 degrees is a slope of 5.24 centimeters per meter. (rounded)
How much fall in a degree roof over 5 meter?
Approx 0.087 metres.
How much is 6 degree fall over 3.1 metres?
It is 32 cm.
How much fall in a 1 degree roof over 10 meter?
10*sin(1) metres = 0.175 metres = 17.5 cm.
How much fall in a 1 degree roof over 1 meter?
Approx 0.087 metres.
How much fall in 1 degree roof over 1 meter?
Approx 0.087 metres.
How much fall in 10 degrees over 1 metre?
160mm
How much fall over 1.23 meters is 3 degrees?
all
How much does a 15 degree ramp fall over 3.8 metres?
Approx 98 centimetres.
How much fall in a 2 degree roof over 2 metres?
To calculate the fall (or slope) of a roof, you can use the formula for slope, which is rise over run. For a 2-degree angle over a horizontal distance of 2 metres, you can use the tangent function: ( \text{rise} = \text{run} \times \tan(\text{angle}) ). Thus, the fall would be approximately ( 2 , \text{m} \times \tan(2^\circ) ), which results in about 0.07 metres, or 7 millimetres.
How much fall is 5 degrees over 1.8 meters?
To calculate the fall over a distance of 1.8 meters for a 5-degree angle, you can use the formula: fall = distance × sin(angle). In this case, fall = 1.8 meters × sin(5 degrees) ≈ 1.8 × 0.0872 ≈ 0.157 meters, or about 15.7 centimeters.
How much fall is there in 2 degrees over 10 meters?
To calculate the fall over a distance of 10 meters at a 2-degree slope, you can use the formula for vertical drop: fall = distance × sin(angle). Substituting the values, you get a fall of approximately 0.35 meters (or 35 centimeters) over 10 meters.
How much fall in a 5 degree roof over 6 metres?
To calculate the fall over a 5-degree roof pitch over a 6-meter span, you can use the tangent of the angle. The height (fall) is equal to the length multiplied by the tangent of the angle: ( \text{Fall} = 6 , \text{m} \times \tan(5^\circ) ). This results in approximately 0.52 meters, or 52 centimeters of fall over the 6-meter length.
