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To calculate the vertical fall over a horizontal distance at a given angle, you can use trigonometry. In this case, the fall at 2 degrees over 6 meters can be calculated using the formula: vertical fall = horizontal distance * tan(angle). Plugging in the values, the vertical fall would be approximately 0.21 meters, or 21 centimeters.
What else can I help you with?
How much fall in a 1 degree roof over 10 meter?
10*sin(1) metres = 0.175 metres = 17.5 cm.
How much fall in 10 degrees over 1 metre?
160mm
How much fall in a 2 degree foor over 3.9 mts?
To find the slope or fall of a ball or other object that is at an angle of 2 degrees for over 3.9 minutes, you will need several factors. You will need the distance or length of the slope and the speed of the ball at its peak movement.
How much fall in a 3 degree roof over 7 meter?
30cm
How many degrees does a obtuse have?
over 90 degrees
How much fall in a degree roof over 5 meter?
Approx 0.087 metres.
How much is 6 degree fall over 3.1 metres?
It is 32 cm.
How much fall in 1 degree roof over 1 meter?
Approx 0.087 metres.
How much fall in a 1 degree roof over 1 meter?
Approx 0.087 metres.
How much fall in a 1 degree roof over 10 meter?
10*sin(1) metres = 0.175 metres = 17.5 cm.
How much fall over 1.23 meters is 3 degrees?
all
How much fall in 10 degrees over 1 metre?
160mm
How much does a 15 degree ramp fall over 3.8 metres?
Approx 98 centimetres.
How much fall is 5 degrees over 1.8 meters?
To calculate the fall over a distance of 1.8 meters for a 5-degree angle, you can use the formula: fall = distance × sin(angle). In this case, fall = 1.8 meters × sin(5 degrees) ≈ 1.8 × 0.0872 ≈ 0.157 meters, or about 15.7 centimeters.
How much is 4 degrees fall over 1 metre?
A fall of 4 degrees over 1 meter refers to a slope or incline where the vertical drop is 4 degrees relative to the horizontal. To calculate the vertical drop, you can use the tangent function: the vertical drop is approximately 0.07 meters (or 7 centimeters) over 1 meter of horizontal distance. This represents a gentle slope, as 4 degrees is a small angle.
How much fall in a 5 degree roof over 6 metres?
To calculate the fall over a 5-degree roof pitch over a 6-meter span, you can use the tangent of the angle. The height (fall) is equal to the length multiplied by the tangent of the angle: ( \text{Fall} = 6 , \text{m} \times \tan(5^\circ) ). This results in approximately 0.52 meters, or 52 centimeters of fall over the 6-meter length.
How much fall is 2 degrees roof over 3 meters?
Three times the answer to the related question below.
