To calculate the vertical fall over a horizontal distance at a given angle, you can use trigonometry. In this case, the fall at 2 degrees over 6 meters can be calculated using the formula: vertical fall = horizontal distance * tan(angle). Plugging in the values, the vertical fall would be approximately 0.21 meters, or 21 centimeters.
10*sin(1) metres = 0.175 metres = 17.5 cm.
160mm
To find the slope or fall of a ball or other object that is at an angle of 2 degrees for over 3.9 minutes, you will need several factors. You will need the distance or length of the slope and the speed of the ball at its peak movement.
30cm
over 90 degrees
Approx 0.087 metres.
It is 32 cm.
Approx 0.087 metres.
Approx 0.087 metres.
10*sin(1) metres = 0.175 metres = 17.5 cm.
160mm
all
Approx 98 centimetres.
A fall of 4 degrees over 1 meter refers to a slope or incline where the vertical drop is 4 degrees relative to the horizontal. To calculate the vertical drop, you can use the tangent function: the vertical drop is approximately 0.07 meters (or 7 centimeters) over 1 meter of horizontal distance. This represents a gentle slope, as 4 degrees is a small angle.
Three times the answer to the related question below.
To find the slope or fall of a ball or other object that is at an angle of 2 degrees for over 3.9 minutes, you will need several factors. You will need the distance or length of the slope and the speed of the ball at its peak movement.
0.5 metres.0.5 metres.0.5 metres.0.5 metres.