Sn = 3n2 + 2n - 8
The nth term is: 5-6n
Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}
t(n) = 28-3n where n = 1,2,3,...
The nth term is 9n-2
As given, the sequence is too short to establish the generating rule. If the second term was 19 and NOT 29, then the nth term is tn = 6*n + 7 or 6(n+1)+1
The nth term is 6n+1 and so the next term will be 31
The nth term is: 5-6n
Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}
It is 4n+5 and so the next term will be 25
tn = n2
t(n) = 28-3n where n = 1,2,3,...
The nth term is 9n-2
As given, the sequence is too short to establish the generating rule. If the second term was 19 and NOT 29, then the nth term is tn = 6*n + 7 or 6(n+1)+1
The given sequence is an arithmetic sequence where each term increases by 4. The first term (a) is 13, and the common difference (d) is 4. The nth term can be found using the formula: ( a_n = a + (n-1)d ). Therefore, the nth term is ( a_n = 13 + (n-1) \cdot 4 = 4n + 9 ).
25
Oh honey, looks like we're counting down by 4 each time. So, if we keep that pattern going, the next number would be 5. So, the nth term in this sequence is 21 - 4n, where n is the position of the term in the sequence.
work it out it's one more than the 8th and one less than the 10th * * * * * The above answer seems to make no sense here. It is not clear what you mean by a fraction sequence. It is not possible to go through the process for finding the nth term in an arithmetic, geometric or power sequence here. For school mathematics, sequences of fractions are, in fact composed of two simple sequences. One sequence defines the numerators and the other defines the denominators. In such cases, the nth term of the fraction sequence is the fraction given by the nth term of the numerator sequence divided by the nth term of the denominator sequence. For example: 1/1, 3/4, 5/9, 7/16, 9/25, ... The numerators are the odd number, with t(n) = 2n-1 The denominators are the squares of natural numbers with u(n) = n2 So, the nth term of the fraction sequence is (2n-1)/n2.