tn = n2
To determine the nth term of the sequence 25, 16, 7, we first identify the pattern. The sequence appears to be decreasing by 9, then by 9 again, suggesting a consistent difference. This leads to a formula for the nth term: ( a_n = 34 - 9n ), where ( a_1 = 25 ) for n=1. Thus, the nth term can be expressed as ( a_n = 34 - 9n ).
tn = 34 - 9n where n = 1,2,3,...
The sequence 11, 18, 25, 32, 39 has a common difference of 7. To find the nth term, we can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_1 = 11 ) and ( d = 7 ). Thus, the nth term is given by ( a_n = 11 + (n-1) \times 7 = 7n + 4 ).
The sequence 1, 7, 13, 19, 25 is an arithmetic sequence where each term increases by 6. The first term (a) is 1, and the common difference (d) is 6. The nth term can be expressed using the formula: ( a_n = a + (n - 1)d ). Therefore, the nth term is ( a_n = 1 + (n - 1) \cdot 6 = 6n - 5 ).
The given sequence is an arithmetic sequence where each term increases by 4. The first term (a) is 13, and the common difference (d) is 4. The nth term can be found using the formula: ( a_n = a + (n-1)d ). Therefore, the nth term is ( a_n = 13 + (n-1) \cdot 4 = 4n + 9 ).
Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}
To determine the nth term of the sequence 25, 16, 7, we first identify the pattern. The sequence appears to be decreasing by 9, then by 9 again, suggesting a consistent difference. This leads to a formula for the nth term: ( a_n = 34 - 9n ), where ( a_1 = 25 ) for n=1. Thus, the nth term can be expressed as ( a_n = 34 - 9n ).
The nth term is: 5-6n
The nth term is 9n-2
It is 4n+5 and so the next term will be 25
t(n) = 28-3n where n = 1,2,3,...
n2
The nth term = 9n-2
(n+1)^2 Please tell me you know what that means.
Sn = 3n2 + 2n - 8
tn = 34 - 9n where n = 1,2,3,...
The sequence 11, 18, 25, 32, 39 has a common difference of 7. To find the nth term, we can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_1 = 11 ) and ( d = 7 ). Thus, the nth term is given by ( a_n = 11 + (n-1) \times 7 = 7n + 4 ).