The area ,A, of a rectangle is the length, L, multiplied by the width, W. A=LW hence W=A/L. The perimeter, P, of a rectangle is P= 2(L+W) or 2L+2W. 2W=P-2L and W=(P/2)-L. The Square of the diagonal of a rectangle, D^2 =W^2+L^2 so that W^2=D^2-L^2 and W=sqrt((D^2-L^2). You could also express the width using trigonometric functions, but this is probably enough to get you started.
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The formula for perimeter of a rectangle is: P=2L+2W where L is the length and W is the width of the rectangle.
length times width
2
I beleve that is the formula for finding the area of a rectangle or squareLength*Width equals area for rectangles. LxW=Area of a rectangle.
Let the width of the rectangle be represented by "w" inches. Since the length is twice the width, it can be expressed as "2w" inches. The formula for the perimeter of a rectangle is P = 2(l + w), where P is the perimeter, l is the length, and w is the width. Substituting the given values into the formula, we get 48 = 2(2w + w). Simplifying, we find that 48 = 6w. Solving for w, we find that the width of the rectangle is 8 inches, and the length is 16 inches.