0
A solution for 4th difference sequence is:
Formula: Tn = an4+ bn3+ cn2 + dn + e
1st term = a + b + c + d + e
1st difference = 15a + 7b + 3c + d
2nd difference = 50a + 12b + 2c
3rd difference = 60a + 6b
4th difference = 24a
Example:
Tn (term number) = 1 2 3 4 5 6 7
Sequence = 1 41 209 643 1529 3101 5641
1st difference = 40 168 434 886 1572 2540
2nd difference = 128 266 452 686 968
3rd difference = 138 186 234 282
4th difference = 48 48 48
Step 1: 4th difference = 24a:
24a = 48
a = 2
Step 2: 3rd difference = 60a + 6b:
60(2) + 6b = 138
b = 3
Step 3: 2nd difference = 50a + 12b + 2c:
50(2) + 12(3) + 2c = 128
c = -4
Step 4: 1st difference = 15a + 7b + 3c + d:
15(2) + 7(3) + 3(-4) + d = 40
d = 1
Step 5: 1st 1st term = a + b + c + d + e:
2 + 3 - 4 + 1 + e = 1
e = -1
Answer:
Tn = 2n4+ 3n3- 4n2 + n - 1
What else can I help you with?
A sequence has nth term formula 3n+5. What is the fourth term?
8
How do you find out the formula for a Quadratic Sequence?
A quadratic sequence is when the difference between two terms changes each step. To find the formula for a quadratic sequence, one must first find the difference between the consecutive terms. Then a second difference must be found by finding the difference between the first consecutive differences.
What is the formula for the nth term of this sequence 17 29 41 53 65 77?
t(n) = 12*n + 5
What is the formula for the nth term of this sequence 14 22 30 38 46?
Oh, dude, you're hitting me with the math questions, huh? So, the formula for finding the nth term of an arithmetic sequence is a + (n-1)d, where a is the first term and d is the common difference. In this sequence, the common difference is 8 (because each term increases by 8), and the first term is 14. So, the formula for the nth term would be 14 + 8(n-1). You're welcome.
Which is the term number when the term value is 53?
To find the term number when the term value is 53 in a sequence, you need to know the pattern or formula of the sequence. If it is an arithmetic sequence with a common difference of d, you can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_n ) is the nth term, ( a_1 ) is the first term, and d is the common difference. By plugging in the values, you can solve for the term number.
What is the difference between a geometric sequence and a recursive formula?
what is the recursive formula for this geometric sequence?
A sequence has nth term formula 3n+5. What is the fourth term?
8
How do you find out the formula for a Quadratic Sequence?
A quadratic sequence is when the difference between two terms changes each step. To find the formula for a quadratic sequence, one must first find the difference between the consecutive terms. Then a second difference must be found by finding the difference between the first consecutive differences.
What is the formula for the nth term of this sequence 17 29 41 53 65 77?
t(n) = 12*n + 5
What is the formula for the nth term of this sequence 14 22 30 38 46?
Oh, dude, you're hitting me with the math questions, huh? So, the formula for finding the nth term of an arithmetic sequence is a + (n-1)d, where a is the first term and d is the common difference. In this sequence, the common difference is 8 (because each term increases by 8), and the first term is 14. So, the formula for the nth term would be 14 + 8(n-1). You're welcome.
Is one one fourth one seventh one tenth a arithemtic sequence?
An arithmetic sequence is a sequence of numbers where the difference is constant. The difference between 1 and 1/4 is 3/4. The difference between 1/4 and 1/7 is 3/28. The difference between 1/7 and 1/10 is 3/70. These differences are not constant.
What does common difference mean?
In mathematics, the common difference refers to the constant amount that is added or subtracted in each step of an arithmetic sequence. It is the difference between any two consecutive terms in the sequence. For example, in the sequence 2, 5, 8, 11, the common difference is 3, as each term increases by this amount. This concept helps in determining the formula for the nth term of an arithmetic sequence.
How is a arithmetic sequence found?
You take the difference between the second and first numbers.Then take the difference between the third and second numbers. If that difference is not the same then it is not an arithmetic sequence, otherwise it could be.Take the difference between the fourth and third second numbers. If that difference is not the same then it is not an arithmetic sequence, otherwise it could be.Keep checking until you think the differences are all the same.That being the case it is an arithmetic sequence.If you have a position to value rule that is linear then it is an arithmetic sequence.
What is the nth term formula to 3 7 11?
The sequence 3, 7, 11 is an arithmetic sequence where the first term is 3 and the common difference is 4. The nth term formula for an arithmetic sequence can be expressed as ( a_n = a_1 + (n - 1)d ), where ( a_1 ) is the first term and ( d ) is the common difference. Substituting the values, the nth term formula for this sequence is ( a_n = 3 + (n - 1) \cdot 4 ), which simplifies to ( a_n = 4n - 1 ).
Does Every sequence have a formula associated with it?
no not every sequence has a formula associated with it.
How do you work out the 20th term of a sequence?
To find the 20th term of a sequence, first identify the pattern or formula that defines the sequence. This could be an arithmetic sequence, where each term increases by a constant difference, or a geometric sequence, where each term is multiplied by a constant factor. Once the formula is established, substitute 20 into the formula to calculate the 20th term. If the sequence is defined recursively, apply the recursive relation to compute the 20th term based on the previous terms.
How do you create a sequence in which 1 and one fourth is added to each number?
To form a linear (or arithmetic) sequence you need two things: a starting value and the common difference. You have provided the common difference but not the starting value. If the starting value was a, then the nth term in the sequence would beT(n) = a + 5/4*(n - 1).
