A solution for 4th difference sequence is:
Formula: Tn = an4+ bn3+ cn2 + dn + e
1st term = a + b + c + d + e
1st difference = 15a + 7b + 3c + d
2nd difference = 50a + 12b + 2c
3rd difference = 60a + 6b
4th difference = 24a
Example:
Tn (term number) = 1 2 3 4 5 6 7
Sequence = 1 41 209 643 1529 3101 5641
1st difference = 40 168 434 886 1572 2540
2nd difference = 128 266 452 686 968
3rd difference = 138 186 234 282
4th difference = 48 48 48
Step 1: 4th difference = 24a:
24a = 48
a = 2
Step 2: 3rd difference = 60a + 6b:
60(2) + 6b = 138
b = 3
Step 3: 2nd difference = 50a + 12b + 2c:
50(2) + 12(3) + 2c = 128
c = -4
Step 4: 1st difference = 15a + 7b + 3c + d:
15(2) + 7(3) + 3(-4) + d = 40
d = 1
Step 5: 1st 1st term = a + b + c + d + e:
2 + 3 - 4 + 1 + e = 1
e = -1
Answer:
Tn = 2n4+ 3n3- 4n2 + n - 1
8
A quadratic sequence is when the difference between two terms changes each step. To find the formula for a quadratic sequence, one must first find the difference between the consecutive terms. Then a second difference must be found by finding the difference between the first consecutive differences.
t(n) = 12*n + 5
To find the term number when the term value is 53 in a sequence, you need to know the pattern or formula of the sequence. If it is an arithmetic sequence with a common difference of d, you can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_n ) is the nth term, ( a_1 ) is the first term, and d is the common difference. By plugging in the values, you can solve for the term number.
In this case, 22 would have the value of 11.
what is the recursive formula for this geometric sequence?
8
A quadratic sequence is when the difference between two terms changes each step. To find the formula for a quadratic sequence, one must first find the difference between the consecutive terms. Then a second difference must be found by finding the difference between the first consecutive differences.
t(n) = 12*n + 5
An arithmetic sequence is a sequence of numbers where the difference is constant. The difference between 1 and 1/4 is 3/4. The difference between 1/4 and 1/7 is 3/28. The difference between 1/7 and 1/10 is 3/70. These differences are not constant.
You take the difference between the second and first numbers.Then take the difference between the third and second numbers. If that difference is not the same then it is not an arithmetic sequence, otherwise it could be.Take the difference between the fourth and third second numbers. If that difference is not the same then it is not an arithmetic sequence, otherwise it could be.Keep checking until you think the differences are all the same.That being the case it is an arithmetic sequence.If you have a position to value rule that is linear then it is an arithmetic sequence.
no not every sequence has a formula associated with it.
Since the difference between each term is '4' , then the first part of the formula is '4n'.
Finding the nth term is much simpler than it seems. For example, say you had the sequence: 1,4,7,10,13,16 Sequence 1 First we find the difference between the numbers. 1 (3) 4 (3) 7 (3) 10 (3) 13 (3) 16 The difference is the same: 3. So the start of are formula will be 3n. If it was 3n, the sequence would be 3,6,9,12,15,18 Sequence 2 But this is not our sequence. Notice that each number on sequence 2 is 2 more than sequence 1. this means are final formula will be: 3n+1 Test it out, it works!
To form a linear (or arithmetic) sequence you need two things: a starting value and the common difference. You have provided the common difference but not the starting value. If the starting value was a, then the nth term in the sequence would beT(n) = a + 5/4*(n - 1).
To find the term number when the term value is 53 in a sequence, you need to know the pattern or formula of the sequence. If it is an arithmetic sequence with a common difference of d, you can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_n ) is the nth term, ( a_1 ) is the first term, and d is the common difference. By plugging in the values, you can solve for the term number.
In this case, 22 would have the value of 11.