a2b3
The standard size of an index card is 3 X 5.
2t x 3t = 6t2
2 x 2 x 2 x a x a x a x b x b
Let the number be X, then B% = B/100 → B% of X = C → B/100 x X = C → X = C ÷ (B/100) = C x 100/B = 100C ÷ B So to find the number, divide C by B percent.
Oh, that's a happy little question! Let's break it down gently. To express 96 as a product of its prime factors using index notation, we first find the prime factors of 96, which are 2 x 2 x 2 x 2 x 2 x 3. Then, we can write this as 2^5 x 3. And just like that, we've created a beautiful representation of 96 using its prime factors and index notation.
X^â x X^b= x^â+b x^a divided by x^b = x^a+b (x^a)^b=x^ab x^0=1 x^-a=1/x^a
X^â x X^b= x^â+b x^a divided by x^b = x^a+b (x^a)^b=x^ab x^0=1 x^-a=1/x^a
X^â x X^b= x^â+b x^a divided by x^b = x^a+b (x^a)^b=x^ab x^0=1 x^-a=1/x^a
X^â x X^b= x^â+b x^a divided by x^b = x^a+b (x^a)^b=x^ab x^0=1 x^-a=1/x^a
It follows from the index laws. x^(a-b) = x^a / x^b If you then set b = a then x^0 = x^a/x^a = 1.
A number with a negative index is simply the reciprocal of the same number with a positive index. So, x-a = 1/xa Next a number to a fractional index, (a/b) is the ath power of the bth root of the number. Equivalently, it is the bth root of the ath power of the number. That is, xa/b = b√(xa) = (b√x)a. Combining these results: x-a/b = 1/(xa/b) = 1/[b√(xa)]
Here's a start umbers=[True]*5001 index=2 primes=[] while index<5000: multiplier=2 while index*multiplier <= 5000: Numbers[index*multiplier]=False multiplier+=1 index+=1 while Numbers[index]==False and index < 5000: index+=1 for x in range(0,5000): if Numbers[x]==True: primes.append(x) x+=1 print primes
(x - a) + (x - a) + (b) = 2 (x - a) + (b) = x - a + x - a + b = 2x - 2a + b
A condensed form of a * a * b * b * b is a2 * b3.a * a * b * b * b = a2 * b3
B. Thomas Byrne has written: 'The Stock Index Futures Market' -- subject(s): Stock index futures
x^a / x^b = x^(a-b)andx^a * x^b = x^(a+b)
This is the prime factorization of 80 in index form: 80 = 2 x 2 x 2 x 2 x 5 = 24 x 5