sqrt(x^3)
(x^3)^.5
x^1.5 1.5+1=2.5 1/2.5=.4
Answer: .4x^2.5+c
The general form is (2/3)*x^(3/2) + C
The answer is -i
48,558.703555593409190891730197596
It's the same
There is no formula relating to a perfect square but if you want a method 1. Find square root(x) 2. Take the integer component (integral value) of square root(x) 3 Add 1 to intenger(square root(x)) 4. square it So: (integer(square root(x)) + 1)^2
The answer is -i
9 times the square root of 3
4^3√32-3^3√108+^3√256
The general form is (2/3)*x^(3/2) + C
This is an easy question : root 2, root 3, root 5. Any square root of an integer which is not integral itself is irrational.
3/(4*square root(x)) ....Mukesh
You divide the exponent by 2 The square root of a number is that number to the 1/2 power So for examle square root of x cubed (x^3) is x^3 to the half power =x^3/2 (x to the 3/2 power)
it means you need to do B to the power m, then take the nth root of your answer. eg 9 to the power 3/2, means you do 9 cubed and then square root your answer. in this case, its easier to do the square root first and then cube your answer as the square root of 9 is 3, and 3 cubed is 27. therefore 3 to the power 3/2 equals 27
3
48,558.703555593409190891730197596
343
No. A square number is one that has an integral as its square root. For example, 9 is a square number because 3 x 3 = 9. There is no whole number that gives you 11 when multiplied by itself.