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it means you need to do B to the power m, then take the nth root of your answer.
eg 9 to the power 3/2, means you do 9 cubed and then square root your answer. in this case, its easier to do the square root first and then cube your answer as the square root of 9 is 3, and 3 cubed is 27. therefore 3 to the power 3/2 equals 27
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How do you find the power of a quotient?
The power of a quotient is the quotient of the power! (a/b)^n = (a^n) / (b^n) where a/b is the quotient and n is the power.
How do you solve a to the power of m times a to the power of n?
You don't solve it!!! It is a method of manipulation of indices. a^(n) X a^(m) = a^(n+m) Similarly, a^(n) / a^(m) = a^(n-m) [a^(n)]^(m) = a^(nm)
If a is congruent to b mod m and a is also congruent to b mod n what is the relationship between m and n?
There need not be any. Consider (a, b, m, n) = (37, 2, 35, 7) where n is a factor of m.or (a, b, m, n) = (37, 2, 5, 7) where m and n are relatively prime.
When M equals 25 and N equals -6 than what is M divided by 5?
When M equals 25, then M divided by 5 is 5. It makes no difference what N is.
Rules in multiplying or deviding in scientific notation?
To multiply m x 10a by n x 10b: multiply the numbers (m x n) add the powers (a + b) (m x 10a) x (n x 10b) = mn x 10a+b To divide m x 10a by n x 10b: divide the numbers (m / n) subtract the powers (a - b) (m x 10a) / (n x 10b) = m/n x 10a-b
What are laws of exponents?
x^a is x time itself a number of timesx^0=1 any number raised to the zero power equals 1x^n times x^m = x^(n+m)x^n divided by x^m = x^(n-m)x^(1/n) is the n-th root of xx^(-1) is 1/x(mathematics) Any of the laws aman am+n, am/an am-n, (am)n amn, (ab)n anbn, (a/b)n = an/bn; these laws are valid when m and n are any integers, or when a and b are positive and m and n are any real numbers. Also known as exponential law.
How do you find the power of a quotient?
The power of a quotient is the quotient of the power! (a/b)^n = (a^n) / (b^n) where a/b is the quotient and n is the power.
How do you solve a to the power of m times a to the power of n?
You don't solve it!!! It is a method of manipulation of indices. a^(n) X a^(m) = a^(n+m) Similarly, a^(n) / a^(m) = a^(n-m) [a^(n)]^(m) = a^(nm)
If a is congruent to b mod m and a is also congruent to b mod n what is the relationship between m and n?
There need not be any. Consider (a, b, m, n) = (37, 2, 35, 7) where n is a factor of m.or (a, b, m, n) = (37, 2, 5, 7) where m and n are relatively prime.
When M equals 25 and N equals -6 than what is M divided by 5?
When M equals 25, then M divided by 5 is 5. It makes no difference what N is.
When you add a number that has a remainder of 1 when it is divided by 3 to a number that has a remainder of 2 when it is divided by 3 then what is the remainder of the sum when you divide it by 3?
The remainder is 0.If A has a remainder of 1 when divided by 3, then A = 3m + 1 for some integer mIf B has a remainder of 2 when divided by 3, then B = 3n + 1 for some integer n→ A + B = (3m + 1) + (3n + 2)= 3m + 3n + 1 + 2= 3m + 3n + 3= 3(m + n + 1)= 3k where k = m + n + 1 and is an integer→ A + B = 3k + 0→ remainder when A + B divided by 3 is 0-------------------------------------------------------------------------From this, you may be able to see that:if A when divided by C has remainder Ra; andif B when divided by C has remainder Rb; then(A + B) divided by C will have remainder equal to the remainder of (Ra + Rb) divided by C
Why is a negative divided by a negative a positive?
if we have two negative numbers, -n and -m and we divide them: (-n)/(-m) then we can rewrite the quotient as : (-1)*n/(-1)*m and... (-1)/(-1) * n/m we know that any number divided by itself is 1 by some rule: so = (-n)/(-m) = n/m which is positive
How do you solve M to the power of 4 times N to the power of 5 minus M to the power of 20 times N to the power of 21 m4 n5 - m20n21?
m^4 n^5 - m^20 n^21
When a positive integer is raised to the power of zero the answer is always one. Why?
You can understand this by using one rule of exponents. For integers m,n, and positive integer a a^m/a^n=a^(m-n) So if we look at a^m/a^m which must be 1 since it is something divided by itself, we know from the rule we can also write this as a^(n-n)=a^0 but we just showed that was 1.
What do they mean by a to the b power times a to the c power equals a b c power?
ab*ac=ab+c consider the powers of 2. 22=4, 23=8, 22*23=32=23+2=25 when multiplying a number by itself, you raise its power by one. when multiplying a number by itself n times, you raise it to the power of n, so if you raise a number to the power n, then the seame number to the power m, then multiply these together you are multiplying n+m times
What does a number to the power of zero equal?
Any number to the power '0' equals '1'. Proof ; Let a^(n) = b Then dividing a^(n) / a^(n) = b/b a^(n-n) = b/b a^(0) = 1
Rules in multiplying or deviding in scientific notation?
To multiply m x 10a by n x 10b: multiply the numbers (m x n) add the powers (a + b) (m x 10a) x (n x 10b) = mn x 10a+b To divide m x 10a by n x 10b: divide the numbers (m / n) subtract the powers (a - b) (m x 10a) / (n x 10b) = m/n x 10a-b
