3x-y=9 y=3x-9
-9
y = (4x+9)/(2x+3)2xy+3y = 4x+93y-9 = 4x-2xy3y-9 = x(2-2y)x = (3y-9)/(2-2y)So, inverse function is 3x minus 9 divided by 2 minus 27.
same x intercept as y = 3x -9 x intercept is when y = 0 0 = 3x-9 3x = 9 x = 3, the same x intercept Now find the line parallel to 3x+y = 0 with x intercept = +3 Since line is parallel it has the same slope 3x+y = 0 y = -3x +0 standard form where the number in front of x is slope, = -3 Thus y = -3x + b but we know x intercept (when y = 0) is +3 0 = -3(3) + b solve b = +9 the parallel line is y = -3x+9
Well, if 3x equals 12, then x equals 4. And if y equals 3x, then y equals 3 times 4, which is 12. So, y equals 12. Math can be a piece of cake when you break it down like that!
6
3x-y=9 y=3x-9
f(x) = 3x + 9 y = 3x + 9 so 3x = y - 9 x = y/3 - 3 Therefore, the inverse function is g(x) = x/3 - 3
6
y = 3x + y => x = 0then y = x - 9 => y = 0 - 9 = -9.
-9
3x-6y=9 -3x -3x -6y=9-3x __ ____ -6 -6 y=9-3x ____ -6
y = 3x + 2 y-2 = 3x x = (y-2)/3 So the inverse is (x-2)/3
y = 3x + 8Replace x with y and y with x.x = 3y + 8Solve for y.x - 8 = 3y3y = x - 8y = (x-8)/3
3x-y = 9 2x+y = 6 Add both equations together: 5x = 15 x = 3 and y = 0
3x+y=-1 y=-1-3x5x-y=9 5x-(-1-3x)=95x+1+3x=98x=8x=1y=-1-3(1)y=-4(1,-4)
your equation is y=3x + 4 here are five parallel equations... y=3x + 5 y=3x + 6 y=3x + 7 y=3x + 8 y=3x + 9