You need to spell out mathematical operations in your question, or they will come out as above, ambiguously. Use plus, minus, times, divided by, and any other operations you want in your equations.
3x-y=9 y=3x-9
-9
y = (4x+9)/(2x+3)2xy+3y = 4x+93y-9 = 4x-2xy3y-9 = x(2-2y)x = (3y-9)/(2-2y)So, inverse function is 3x minus 9 divided by 2 minus 27.
y = 3x = 12y = 12
same x intercept as y = 3x -9 x intercept is when y = 0 0 = 3x-9 3x = 9 x = 3, the same x intercept Now find the line parallel to 3x+y = 0 with x intercept = +3 Since line is parallel it has the same slope 3x+y = 0 y = -3x +0 standard form where the number in front of x is slope, = -3 Thus y = -3x + b but we know x intercept (when y = 0) is +3 0 = -3(3) + b solve b = +9 the parallel line is y = -3x+9
6
3x-y=9 y=3x-9
6
f(x) = 3x + 9 y = 3x + 9 so 3x = y - 9 x = y/3 - 3 Therefore, the inverse function is g(x) = x/3 - 3
y = 3x + y => x = 0then y = x - 9 => y = 0 - 9 = -9.
-9
3x-6y=9 -3x -3x -6y=9-3x __ ____ -6 -6 y=9-3x ____ -6
y = 3x + 2 y-2 = 3x x = (y-2)/3 So the inverse is (x-2)/3
y = 3x + 8Replace x with y and y with x.x = 3y + 8Solve for y.x - 8 = 3y3y = x - 8y = (x-8)/3
3x-y = 9 2x+y = 6 Add both equations together: 5x = 15 x = 3 and y = 0
3x+y=-1 y=-1-3x5x-y=9 5x-(-1-3x)=95x+1+3x=98x=8x=1y=-1-3(1)y=-4(1,-4)
your equation is y=3x + 4 here are five parallel equations... y=3x + 5 y=3x + 6 y=3x + 7 y=3x + 8 y=3x + 9