f(x) = 3x + 9 y = 3x + 9 so 3x = y - 9 x = y/3 - 3 Therefore, the inverse function is g(x) = x/3 - 3
x^2 + 3x + 2/(-3x) - x^2 - 2=3x-2+2/(-3x)=3x-2-2/(3x)
3x + (-2 + 4x) = -2 + 7x
The sum of 3x plus 2 and -4 plus 3 is 3x+1 if the equation is (3x+2)+(-4+3). If they are two separate questions, 3x+2 remains as itself while -4+3=-1.
The additive inverse is x5 + 2x - 2.
If you mean: y-2 = 3x+2 then as a straight line equation it is y = 3x+4
To write the inverse, you replace negatives with positives (and vice versa). Thus, for -3x + 5, it would be 3x - 5.
This is only half of an equation. If -x^2 + 3x +2y = 0, then x^2 -3x = 2y and y = (x^2-3x)/2 Solving for x is the inverse, but difficult without a second equation.
x^2 + 3x - 2; -x^2 - 3x + 2andx - 1; 1 - x
3x + 2 = 3x + 6 This is not possible.
f(x) = 3x + 9 y = 3x + 9 so 3x = y - 9 x = y/3 - 3 Therefore, the inverse function is g(x) = x/3 - 3
3x+2.
x^2 + 3x + 2/(-3x) - x^2 - 2=3x-2+2/(-3x)=3x-2-2/(3x)
3x-3x+4x^2+8x=4x^2+8x
3x + (-2 + 4x) = -2 + 7x
9x2 + 12x + 4 = 9x2 + 6x + 6x + 4 = 3x(3x + 2) + 2(3x + 2) = (3x + 2)(3x + 2) = (3x + 2)2
The equivalent expression of 3x-9 plus 3x plus 5 is negative 4.