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What is the kinetic energy of a 60.5 gram bullet moving at a velocity of 273 meters per second?
Wiki User
∙ 10y ago
KE = 1/2 M V2 = (0.5) x (0.0605) x (273)2 = 2,254.5 joules (rounded)
That's considerable KE ! It's roughly the same as a 220-pound man moving at 15 mph.
That helps me understand how a bullet can knock a big person down, not to mention
doing some damage to his infrastructure..
Wiki User
∙ 10y ago
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How factors are used to calculate the kinetic energy of an object?
KE = (1/2)mv2 where m = mass (in kilograms), and v = velocity (in meters/second) this gives you the kinetic energy in units of Joules
How much does kinetic energy produce?
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The kinetic energy depends both on the mass and the speed. Convert the speed to meters/second, then use the formula: KE = (1/2)mv2 (kinetic energy = 1/2 x mass times velocity squared).
