That would be 216 - 1, or 65535.
1.157920892 x 1077 (rounded)
216-1 or (2^16)-1
To get the 2s complement, change all 1 bits to 0s and all 0 bits to 1s, and add 1 to the result. So the 2s complement of the 8-bit binary number 10001011 is the binary integer 01110101. If you want that in decimal, then remember that each place value column is twice the value of the place value column to its right, and the rightmost place value column for an integer is 1. Thus 01110101 in decimal is 64 + 32 + 16 + 4 + 1 = 117 (And 10001011 as a signed 8-bit binary integer represents the decimal integer -117.)
1. A single bit can represent two different values, 0 and 1. Then simply take the largest of those two possible values, 1, and that's your answer.
(2^32) - 1
Binary Integer
A 5-bit binary counter, interpreted as an unsigned integer, has a range of 0 to 31. Interpreted as a two's complement signed integer, it has a range of -16 to +15.
15
Largest 8 bit unsigned number is 11111111 binary thus making 255 in decimal.
65,535
300 = 256 + 32 + 8 + 4 = Binary 0000 0001 0010 1100
binary integer don't think so... It's binary digit.
The largest number that can be expressed in six bit binary is 111111, or 63. That however is not prime. Counting down from there, we can see that the first prime below that is 61, which is the answer to the question. Expressed in binary, that would be 111101.
For an unsigned integer, that would be 216-1. For a signed integer in 2's complement notation, the largest number would be 215-1.
6
There are 8 bits in a byte, so a two byte integer would be 16 bits. The largest 16 bit integer possible would be 11111111111111112, which is 65535 in base 10.