If using the compressed format, where a byte holds two decimal digits (because only 4 bits are needed to make nine), so two bytes would be four decimal digits, the largest which is 9999.
65,535
Using the digits 12279, the largest number that can be represented is 97,221.
31 - it's binary equivalent is 11111
A signed 16 bit number can represent the decimal numbers -32768 to 32767.
Explain how an integer can be represented using BCD?
11b which is 1*2 + 1*1 = 3 would be for two bits. But a byte is 8 bits, so 2 bytes is 16 bits. The largest binary number is [2^16 - 1], which is 65535 (base ten)
65,535
Using the digits 12279, the largest number that can be represented is 97,221.
The largest unsigned integer is 26 - 1 = 63, giving the range 0 to 63; The largest signed integer is 25 - 1 = 31, giving the range -32 to 31.
Metric numbers are represented using decimal places rather than fractions usually.
65,535
674
A 6 GB flash drive contains approximately 6 billion bytes. More precisely, since 1 gigabyte (GB) is equal to 1,073,741,824 bytes (using the binary definition), a 6 GB flash drive would have about 6,442,450,944 bytes. However, in decimal terms, it is often rounded to 6,000,000,000 bytes.
If you are using bits and bytes to represent a code, it is referred to as binary representation. This method encodes data using two states, typically represented by 0s and 1s, which are the fundamental units of digital information. In computing, this binary system is essential for processing and storing data.
UTF-16 uses either 2 or 4 bytes per character. Most common characters from the Basic Multilingual Plane (BMP) are encoded using 2 bytes, while characters outside this range require 4 bytes, represented as a pair of 2-byte code units known as surrogates. Therefore, the number of bytes needed depends on the specific characters being encoded.
The largest decimal number that can be stored using 5 bits is 31. This is because 5 bits can represent binary numbers from 00000 (0 in decimal) to 11111 (31 in decimal). The maximum value is calculated as (2^5 - 1), which equals 31.
Bytes can be written using hexadecimal, octal or decimal notation. A numeral with no prefix is always regarded as decimal. If prefixed with a leading zero it is deemed octal and if prefixed with 0x it is deemed hexadecimal. The following shows the three ways to write the decimal value 255: 255 (decimal) 0377 (octal) 0xff (hexadecimal) Hexadecimal is the generally the most convenient method of notation since each hexadecimal digit represents exactly 4-bits (a half byte or a nybble). An octal digit represents exactly 3 bits and is useful for notating bytes in groups of 3 bits. A 24-bit integer is both a multiple of 3 and 4 so it can be notated using 8 octal digits or 6 hexadecimal digits. Individual bytes are best stored using the uint8_t alias (defined in the <cstdint> standard library header) as this guarantees an 8-bit byte in the positive range 0 to 255 decimal. To store several contiguous bytes, use a vector of uint8_t: std::vector<uint8_t> bytes; bytes.push_back (255); bytes.push_back (0377); bytes.push_back (0xff); The above example pushes the value 255 onto the back of the vector three times, using decimal, octal and hexadecimal notation. You can also write contiguous bytes in multiples of 2, 4 and 8 bytes using uint16_t, uint32_t and uint64_t aliases respectively. Thus if you need a 64-bit value, use the uint64_t alias. uint64_t word = 0xffffffffffffffff; // maximum value