Infinity times nine!
99 (= 11 x 9) is the largest multiple of 11 less than 100.
9*11=99
If it's to be a multiple of 9 the its digits must sum to a multiple of 9. Squares under 225 are 196,169,144,121,100... 144 ie 12 squared (and 9 x 16) would seem to be the figure you're looking for.
There is no such number. Since if x were the largest multiple of 3 and 7 then what about 2x? 2x would be a multiple of 3 since x is a multiple of 3; 2x would be a multiple of 7 since x is a multiple of 7; and 2x is bigger than x. So x cannot be the largest.
There is no largest common multiple of any two numbers: whatever common multiple is claimed to be the largest can be increased to an even larger common multiple by adding the lowest common multiple for the numbers (which for 2 and 3 is 6).
The largest common multiple of 6 and 9 is an infinite amount.
It is 11*9 = 99
The largest 3-digit number is 999. To check if it is a multiple of 3, you can sum the digits: 9 + 9 + 9 = 27, which is divisible by 3. Therefore, 999 is the largest 3-digit number that is a multiple of 3.
The largest three-digit number is 999. To determine if it is a multiple of three, we can check if the sum of its digits (9 + 9 + 9 = 27) is divisible by three. Since 27 is divisible by three, 999 is the largest three-digit multiple of three.
99.... 9 times 11
The largest two-digit number that is a multiple of 9 is 90. However, since it must also be even, the largest even two-digit multiple of 9 is 72. Therefore, the largest two-digit number that meets both criteria is 72.
99 (= 11 x 9) is the largest multiple of 11 less than 100.
9*11=99
11 x 9 = 99
If it's to be a multiple of 9 the its digits must sum to a multiple of 9. Squares under 225 are 196,169,144,121,100... 144 ie 12 squared (and 9 x 16) would seem to be the figure you're looking for.
9876543120
11 x 9 = 99 two digits