You get the largest sum if you add all of the numbers.
5/30 + 4/6 = 1/6 + 4/6 = 5/6
4/6, 5/5, 5/6, 6/4, 6/5, 6/6 ie 6 out of 36.
(1, 5, 6, 6), (2, 4, 6, 6), (2, 5, 5, 6), (3, 3, 6, 6), (3, 4, 5, 6), (3, 5, 5, 5), (4, 4, 4, 6), (4, 4, 5, 5).
what is the largest three-digit number that is divisible by 4, 5, and 6
6 x 9 = 54
infinity because numbers are endless
45
There are 216 permutations of three standard dice. Of these, there are exactly 10 that sum to 15, namely 3-3-6, 4-5-6, 4-6-5, 5-4-6, 5-5-5, 5-6-4, 6-3-6, 6-4-5, 6-5-4, and 6-6-3. The probability, then, of rolling a sum of 15 with three standard dice is 10 in 216, or 5 in 108, or about 0.04630.
5/30 + 4/6 = 1/6 + 4/6 = 5/6
Hey ppl sorrry it's not necessary anymore and the answer is not 39.
5/30 + 4/6 = 1/6 + 4/6 = 5/6
4/6, 5/5, 5/6, 6/4, 6/5, 6/6 ie 6 out of 36.
-6, -5 and -4.
(1, 5, 6, 6), (2, 4, 6, 6), (2, 5, 5, 6), (3, 3, 6, 6), (3, 4, 5, 6), (3, 5, 5, 5), (4, 4, 4, 6), (4, 4, 5, 5).
what is the largest three-digit number that is divisible by 4, 5, and 6
The sum of 5/6 and 4/9 is 1 5/18
On two 6-sided fair dice:Rolling a sum of 5: 4 out of 36, or 11.11%Rolling a sum of 7: 6 out of 36, or 16.67%Rolling a sum of either 5 or 7: 10 out of 36, or 27.78%Here's why: Look at the dice as unique, (maybe one is red and one is blue). Then there are 36 different possible outcomes.The four that give a sum of 5: 1+4, 2+3, 3+2, 4+1.The six that give sum of 7: 1+6, 2+5, 3+4, 4+3, 5+2, 6+1So there are 4 chances out of 36 (or 1 out of 9 = 11.11%) to get a sum of 5, and 6 chances out of 36 (or 1 out of 6 = 16.67%) to get a sum of 7. If you want either 5 or 7 as a sum, add the chances together to get 10 out of 36 (or 5 out of 18 = 27.78%)